The correct match of the circled protons in Column $\text{P}$ with the $^1\text{H}$ NMR chemical shift ($\delta\text{ ppm}$) in Column $\text{Q}$ is
P Q I 
A 6.72 II 
B 16.4 III 
C -0.61
To match the circled protons in Column P with their corresponding \(^1\text{H}\) NMR chemical shift in Column Q, we need to understand the typical chemical shifts of different types of protons in \(^1\text{H}\) NMR spectroscopy.
- Examine Compound I:
The circled proton is part of an aromatic ring with a bromine substituent. Aromatic protons typically appear in the range of 6-8 ppm. Hence, the chemical shift of this proton is likely around 6.72 ppm.
- Examine Compound II:
The circled proton is part of an aldehydic group. Aldehydic hydrogens generally appear in the range of 9-10 ppm. However, if the compound also includes substantial deshielding from other electronegative groups, shifts could be higher. The presence of this proton near carbonyl groups likely shifts it significantly downfield to 16.4 ppm.
- Examine Compound III:
The circled proton is part of a cyclohexane ring (sp3 hybridized). Typically, such protons appear between 0–2 ppm. Given the lack of significant deshielding factors, the shift is likely negative or low, around -0.61 ppm.
Based on the above analysis, the correct match is:
- Compound I with option A: 6.72 ppm
- Compound II with option B: 16.4 ppm
- Compound III with option C: -0.61 ppm
Therefore, the correct answer is \(\text{I} - \text{B}; \text{II} - \text{A}; \text{III} - \text{C}\).
Important Questions from Nmr
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