The ${}^{31}\text{P}\{^1\text{H}\}$ NMR experiment involves proton decoupling, meaning any coupling between ${}^{31}\text{P}$ and ${}^1\text{H}$ nuclei is removed. The observed splitting pattern in the ${}^{31}\text{P}$ spectrum arises from coupling between different ${}^{31}\text{P}$ nuclei (P-P coupling).
The compound $2,2,6,6-\text{N}_4\text{P}_4\text{Cl}_4(\text{NMe}_2)_4$ typically refers to a phosphazene cage structure containing a $\text{P}_4\text{N}_4$ framework. The formula indicates 4 phosphorus atoms, 4 nitrogen atoms, 4 chlorine substituents, and 4 dimethylamino ($\text{NMe}_2$) substituents distributed among the phosphorus atoms. The numbering ($2,2,6,6$) suggests a high degree of symmetry, leading to distinct sets of chemically equivalent phosphorus atoms.
In symmetrically substituted $\text{P}_4\text{N}_4$ cages, it is common to have two types of chemically equivalent phosphorus atoms. Let's denote these as Type A and Type B. Due to symmetry, there are likely 4 equivalent phosphorus atoms of Type A and 4 equivalent phosphorus atoms of Type B.
The multiplicity of a signal in NMR depends on the number of equivalent neighboring nuclei it couples to. The number of lines (multiplicity) is given by $2nI + 1$, where $n$ is the number of equivalent neighboring nuclei and $I$ is their nuclear spin ($I = 1/2$ for ${}^{31}\text{P}$).
For a symmetrical $\text{P}_4\text{N}_4$ cage structure with two distinct sets of phosphorus atoms (Type A and Type B):
Therefore, the ${}^{31}\text{P}\{^1\text{H}\}$ NMR spectrum is expected to show two distinct signals, each appearing as a triplet, corresponding to the two different types of phosphorus atoms in the molecule.
In $^1H$ NMR, the multiplicity pattern expected for the highlighted protons in the following compounds is

The number of signals observed in the proton decoupled $^{13}\text{C}$ NMR spectrum of the following compound is