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Question

The number of possible isomers for the square planar mononuclear complex $[(NH_3)_2M(CN)_2]$ of a metal M is

The correct answer is
2

Complex Structure Analysis

The complex given is $[(NH_3)_2M(CN)_2]$.

  • It is a square planar complex.
  • It is mononuclear (contains only one metal atom, M).
  • The ligands are ammonia ($NH_3$) and cyanide ($CN$).
  • The formula type is $MA_2B_2$, where M is the metal, A represents $NH_3$, and B represents $CN$.

Identifying Possible Isomers

For a square planar complex of the type $MA_2B_2$, there are two possible geometric isomers based on the relative positions of the ligands:

  • Cis Isomer: The two identical ligands (in this case, $NH_3$ or $CN$) are adjacent to each other (at a 90° angle).
    • Example arrangement: $NH_3$ ligands at positions 1 and 2, $CN$ ligands at positions 3 and 4.
  • Trans Isomer: The two identical ligands are opposite to each other (at a 180° angle).
    • Example arrangement: $NH_3$ ligands at positions 1 and 3, $CN$ ligands at positions 2 and 4.

Determining the Number of Isomers

In the complex $[(NH_3)_2M(CN)_2]$:

  • The two $NH_3$ ligands can be adjacent (cis) or opposite (trans).
  • The two $CN$ ligands will correspondingly be opposite or adjacent.
  • These two arrangements (cis and trans) represent the only distinct spatial arrangements (stereoisomers).
  • Therefore, there are exactly 2 possible isomers for this complex.

The possible isomers are the cis-diamminedicyanido complex and the trans-diamminedicyanido complex.

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Important Questions from Coordination Chemistry

  1. An aqueous solution of $Co(ClO_4)_2 \cdot 6H_2O$ is light pink in colour. Addition of conc. HCl results in an intense blue coloured solution due to the formation of a new species. The new species among the following is


    [Given: Atomic number of Co = 27]

  2. Among the following, the compound with the lowest CO stretching frequency is
  3. The rates of substitution for the following reaction vary with L in the order 

  4. Identify X in the reaction, $[Pt(NH_3)_4]^{2+} + 2 HCl \rightarrow X$
  5. Among the following octahedral complexes, the one that has the highest enthalpy of hydration is
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