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Question

Among the following, the compound with the lowest CO stretching frequency is

The correct answer is
$[V(CO)_6]^-$

Determining Lowest CO Stretching Frequency

Core Principle: Metal Oxidation State and Back-bonding

The stretching frequency of the Carbonyl ($ CO $) ligand ($ \nu_{CO} $) is sensitive to the electronic environment of the metal center in coordination complexes. Specifically, it depends on the strength of the metal-to-ligand π-back bonding.

  • Stronger π-back bonding leads to increased electron density in the CO π* antibonding orbitals.
  • This weakens the C-O bond, causing a lower $ \nu_{CO} $.
  • π-back bonding is favored by a lower oxidation state (more electron-rich metal) and electron-donating ligands.

Analysis of Metal Oxidation States

Let's determine the oxidation state for the metal in each complex:

  • $ [Mn(CO)_6]^+ $: $ Mn = +1 $
  • $ [V(CO)_6]^- $: $ V = -1 $
  • $ [Cr(CO)_5] $: $ Cr = 0 $
  • $ [Cr(dien)(CO)_3] $: $ Cr = 0 $ (dien is a neutral ligand)

Identifying the Lowest Frequency

The complex with the lowest metal oxidation state will exhibit the strongest π-back bonding and thus the lowest $ \nu_{CO} $.

  • $ V $ in $ [V(CO)_6]^- $ has the lowest oxidation state ($ -1 $).
  • $ Cr $ in $ [Cr(CO)_5] $ and $ [Cr(dien)(CO)_3] $ have an oxidation state of $ 0 $.
  • $ Mn $ in $ [Mn(CO)_6]^+ $ has the highest oxidation state ($ +1 $).

Therefore, $ [V(CO)_6]^- $ has the most electron-rich metal center, leading to the strongest back-bonding and the lowest CO stretching frequency.

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Important Questions from Coordination Chemistry

  1. An aqueous solution of $Co(ClO_4)_2 \cdot 6H_2O$ is light pink in colour. Addition of conc. HCl results in an intense blue coloured solution due to the formation of a new species. The new species among the following is


    [Given: Atomic number of Co = 27]

  2. The rates of substitution for the following reaction vary with L in the order 

  3. Identify X in the reaction, $[Pt(NH_3)_4]^{2+} + 2 HCl \rightarrow X$
  4. Among the following octahedral complexes, the one that has the highest enthalpy of hydration is
  5. Among the given platinum(II) complexes, the one that is thermally the most unstable is

     

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