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Question

Among the given platinum(II) complexes, the one that is thermally the most unstable is

 

The correct answer is

Understanding Platinum(II) Complex Stability

The thermal stability of coordination complexes is determined by the strength of the metal-ligand bonds and the nature of the ligands. The question asks to identify the most thermally unstable platinum(II) complex among the given options.

Analyzing Ligand Effects on Stability

Platinum(II) ($Pt^{2+}$) complexes are typically square planar. Stability is influenced by factors such as:

  • Ligand Type: Chelating ligands (like ethylenediamine, 'en') generally increase stability compared to monodentate ligands.
  • Ligand Lability: Ligands that are easily dissociated or decomposed upon heating reduce thermal stability. Ammonia ($NH_3$) ligands can dissociate at elevated temperatures.
  • Bond Strength: The strength of the $Pt^{2+}$-Ligand bond is crucial.

Identifying the Least Stable Complex

Let's assume the options represent common $Pt^{2+}$ complexes:

  • Option 1: Likely a diammine dichloro complex, e.g., $[Pt(NH3)2Cl2]$.
  • Option 2: Possibly a complex with a chelating ligand, e.g., $[Pt(en)Cl2]$. Chelation enhances stability.
  • Option 3: Likely a tetraammine complex, e.g., $[Pt(NH3)4]Cl2$.
  • Option 4: Possibly a complex with halide ligands, e.g., $K2[PtCl4]$.

Comparing the potential complexes:

  • The tetraammine complex (Option 3) contains four ammonia ligands. Upon heating, ammonia can dissociate relatively easily, leading to decomposition. The reaction might proceed as:

    $ [Pt(NH_3)_4]Cl_2 \xrightarrow{\Delta} \text{Decomposition products} + \text{volatile } NH_3 $

  • Complexes with chelating ligands (Option 2) are generally more stable due to the chelate effect.
  • Complexes with chloride ligands (Option 4) have varying stability, but the lability of ammonia in Option 3 often makes it less thermally stable.
  • The diammine dichloro complex (Option 1) might be more stable than the tetraammine complex.

Therefore, the tetraammineplatinum(II) complex is expected to be the most thermally unstable due to the tendency of ammonia ligands to dissociate upon heating.

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Important Questions from Coordination Chemistry

  1. Consider the figure given below, where M is a metal and L is a monodentate ligand. The $\sigma$-bonding ligand group orbital (LGO) having same symmetry with $d_{z^2}$ orbital of M in the octahedral coordination geometry is

  2. Among the following, the compound with the lowest CO stretching frequency is
  3. The complex(es) that exhibit(s) optical isomerism is (are)
  4. According to Irving-Williams series, the number of d electrons for the first row transition metal (M) ion having the highest overall stability constant (log $\beta$) for $[M(EDTA)]^{2-}$ is ________
  5. Identify X in the reaction, $[Pt(NH_3)_4]^{2+} + 2 HCl \rightarrow X$
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