The Irving-Williams series outlines the trend in stability constants for complexes formed by divalent first-row transition metal ions (like Mn$^{2+}$ through Zn$^{2+}$).
The question asks for the metal ion (M) in the complex $[M(EDTA)]^{2-}$ that possesses the highest overall stability constant ($\log \beta$). Based on the Irving-Williams series, Copper (Cu$^{2+}$) typically forms the most stable complexes among these ions.
To find the number of d electrons for the relevant ion, we examine the electron configuration of Copper (atomic number 29).
The electron configuration of a neutral Copper atom is: $[Ar] 3d^{10} 4s^1$.
When forming the divalent ion, Cu$^{2+}$, two electrons are removed. The electron is lost first from the 4s orbital, and then from the 3d orbital.
The electron configuration for the Cu$^{2+}$ ion is: $[Ar] 3d^9$.
Therefore, the Cu$^{2+}$ ion contains 9 d electrons.
An aqueous solution of $Co(ClO_4)_2 \cdot 6H_2O$ is light pink in colour. Addition of conc. HCl results in an intense blue coloured solution due to the formation of a new species. The new species among the following is
[Given: Atomic number of Co = 27]
The rates of substitution for the following reaction vary with L in the order
