The number 800 is divided in 2 parts such that one part is 9/7 times the other. The larger part is:
450
The question asks us to divide a total number, which is 800, into two distinct parts. We are given a specific relationship between these two parts: one part is \(\frac{9}{7}\) times the other part. Our goal is to find the value of the larger of these two parts.
Let's represent the two unknown parts using variables. Suppose the two parts are \(x\) and \(y\).
From the problem statement, we can form two equations:
\[x + y = 800\]
\[y = \frac{9}{7}x\]
Now we have a system of two linear equations with two variables, \(x\) and \(y\). We can solve this system to find the values of \(x\) and \(y\).
We can use the substitution method to solve this system. Since we already have \(y\) expressed in terms of \(x\) from the second equation, we can substitute the expression for \(y\) into the first equation.
Substitute \(y = \frac{9}{7}x\) into the equation \(x + y = 800\):
\[x + \left(\frac{9}{7}x\right) = 800\]
To solve for \(x\), we need to combine the terms involving \(x\). We can rewrite \(x\) as \(\frac{7}{7}x\) so that it has the same denominator as the other term:
\[\frac{7}{7}x + \frac{9}{7}x = 800\]
Now, add the fractions:
\[\frac{7x + 9x}{7} = 800\] \[\frac{16x}{7} = 800\]
To isolate \(x\), multiply both sides of the equation by 7:
\[16x = 800 \times 7\] \[16x = 5600\]
Now, divide both sides by 16 to find the value of \(x\):
\[x = \frac{5600}{16}\]
Let's perform the division:
\[x = 350\]
So, one part is 350.
Now that we have the value of \(x\), we can find the value of \(y\) using the equation \(y = \frac{9}{7}x\):
\[y = \frac{9}{7} \times 350\]
We can simplify this calculation by dividing 350 by 7 first:
\[y = 9 \times \left(\frac{350}{7}\right)\] \[y = 9 \times 50\] \[y = 450\]
So, the second part is 450.
The two parts are 350 and 450. We need to find the larger part. Comparing the two values:
Clearly, 450 is greater than 350.
We can also verify that 450 is indeed \(\frac{9}{7}\) times 350:
\[\frac{9}{7} \times 350 = 9 \times \frac{350}{7} = 9 \times 50 = 450\]
This confirms our values for \(x\) and \(y\) are correct and satisfy the condition.
The number 800 is divided into two parts, 350 and 450. The larger part is 450.
| Concept | Description | Application in Problem |
|---|---|---|
| Representing Unknowns | Using variables (like \(x, y\)) to represent unknown quantities. | Representing the two parts of 800 as \(x\) and \(y\). |
| Translating Words to Equations | Converting verbal statements into mathematical equations. | "Sum is 800" → \(x+y=800\). "One part is 9/7 times the other" → \(y=\frac{9}{7}x\). |
| Solving System of Equations | Finding values for variables that satisfy multiple equations simultaneously. | Using substitution to solve for \(x\) and \(y\). |
| Fractions and Ratios | Understanding how fractions represent proportions or relationships between quantities. | Using the ratio \(\frac{9}{7}\) to relate the two parts. |
This problem involves the concept of ratios and proportions. When a number is divided into two parts in a certain ratio, say \(a:b\), it means the parts can be represented as \(ak\) and \(bk\) for some constant \(k\). The sum of the parts is \(ak + bk = (a+b)k\). In this problem, one part is \(\frac{9}{7}\) times the other. If one part is \(x\), the other is \(\frac{9}{7}x\). This implies a ratio of \(1 : \frac{9}{7}\), or multiplying by 7, a ratio of \(7:9\).
So, the number 800 is divided in the ratio \(7:9\). The total number of "ratio units" is \(7 + 9 = 16\).
Each ratio unit represents \(\frac{800}{16} = 50\).
The two parts are:
This ratio method confirms our earlier result and provides an alternative way to solve such problems involving dividing a quantity in a given ratio.
The larger part is indeed 450.
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