To find the angle between the graph of a linear equation and the x-axis, we first need to determine the slope of the line. The angle $\theta$ the line makes with the positive x-axis is related to the slope $m$ by the equation $\tan(\theta) = m$. This angle $\theta$ is also called the angle of inclination.
The given linear equation is $35x - 35y + 15 = 0$. We need to rewrite this equation in the slope-intercept form, which is $y = mx + c$, where $m$ is the slope and $c$ is the y-intercept.
$35y = 35x + 15$
$y = \frac{35x}{35} + \frac{15}{35}$
$y = 1x + \frac{3}{7}$
Now, we use the relationship between the slope and the angle of inclination:
$ \tan(\theta) = m $
Substitute the value of the slope we found:
$ \tan(\theta) = 1 $
To find the angle $\theta$, we take the inverse tangent (arctan) of 1:
$ \theta = \arctan(1) $
The angle whose tangent is 1 is $45^\circ$.
Therefore, the measure of the angle between the graph of the linear equation $35x - 35y + 15 = 0$ and the x-axis is $45^\circ$.
Find the co-ordinates of the centroid of a triangle whose vertices are A(1, 4), B(7, 8) and C(10, 12).