The frequency distribution of the hourly wages rate of 100 employees of a paper mill is follows. Find the median wage rate (in ₹).Wages Rate (in ₹) 54-56 56-58 58-60 60-62 62-64 Number of Workers 20 20 20 20 20
59
Cumulative frequencies: 20, 40, 60, 80, 100. With n=100, the median lies in the class where cumulative frequency reaches 50, which is 58-60 (cf before = 40).
Median: \(L+\dfrac{n/2-cf}{f}\times h = 58+\dfrac{50-40}{20}\times2 = 58+1 = 59\).
Hence, the median wage rate is ₹59.
Similar Questions
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6, 9, 15, x + 4, x + 8, x + 12, 30, 32 - The marks scored by 10 students are given below.
17, 19, 12, 20, 19, 14, 15, 18, 19, 14
The mode of the given data is: - Let a set S = {1, 2, 2, 3, 3, 3, 4, 4, 4, 4}. Then the value of $4 \times \text{mean} + 2 \times \text{mode} - 8 \times \text{median}$ is:
- The weights (in kg) of 7 men are 64, 63, 62, 65, 67, 66 and 61. The median weight is:
- Which of the following CANNOT take a negative value?
- The given data is arranged in ascending order and its median is 17. Find the value of $x$.
$8, 10, 12, 15, x, x + 2, 20, 25, 30, 32$ - Find the sum of the mean, median and mode of the given data.
$9, 35, 20, 25, 25, 15, 25$ - In the given data if 30 is replaced by 100 then find the difference of the two medians.
80, 90, 40, 30, 20, 10, 70, 60, 50 - Find the mean height of persons from the following data.
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Value 3 2 k 4 5 Frequency k 2k 3k 4k 5k
Important Questions from Elementary Statistics
In a colony 5 families have 1 child, 7 families have 2 children, 8 families have 3 children and 3 families have 4 children.What is the mode of the number of children.
What will be the difference between mean and median of the given data?
21, 11, 27, 8, 5, 12, 7, 23, 3, 14, 9, 19Find the mode and median of 3, 4, 5, 5, 3, 6, 7, 3, 5, 5, 6.
A. 5 and 5
B. 3 and 5
C. 5 and 4
D. 3 and 4
For which set of numbers do the mean, median and mode all have the same value?
The median of 5, 8, 25, 22, 34, 18 is
