The following table gives the details of the number of students in Class 10 section A and B who had taken the mid-term and final exams. The percentage of students in section A is _____ (round of one decimal). Result Sec A Sec B Total number of students who failed in both exams 28 23 Total number of students who failed in mid-term but passed in finals 14 12 Total number of students who passed in mid-term but failed in finals 6 17 Total number of students who passed in both the exams 64 55
51.4
The question asks us to find the percentage of students in Section A out of the total number of students across both Section A and Section B. We are provided with a table detailing the results of students in mid-term and final exams for both sections.
First, let's understand the data provided in the table:
| Result | Sec A | Sec B |
|---|---|---|
| Total number of students who failed in both exams | 28 | 23 |
| Total number of students who failed in mid-term but passed in finals | 14 | 12 |
| Total number of students who passed in mid-term but failed in finals | 6 | 17 |
| Total number of students who passed in both the exams | 64 | 55 |
To find the percentage of students in Section A, we need two key pieces of information:
We sum the number of students in Section A from all result categories:
Total students in Sec A = (Failed in both) + (Failed mid, Passed final) + (Passed mid, Failed final) + (Passed both)
Total students in Sec A = $28 + 14 + 6 + 64$
Total students in Sec A = $112$
We sum the number of students in Section B from all result categories:
Total students in Sec B = (Failed in both) + (Failed mid, Passed final) + (Passed mid, Failed final) + (Passed both)
Total students in Sec B = $23 + 12 + 17 + 55$
Total students in Sec B = $107$
We add the total students from Section A and Section B:
Total students (Sec A + Sec B) = Total students in Sec A + Total students in Sec B
Total students (Sec A + Sec B) = $112 + 107$
Total students (Sec A + Sec B) = $219$
The percentage of students in Section A is calculated by dividing the total number of students in Section A by the total number of students in both sections and multiplying by 100. The formula is:
Percentage of students in Sec A = $\left( \frac{\text{Total students in Sec A}}{\text{Total students in Sec A + Sec B}} \right) \times 100\%$
Percentage of students in Sec A = $\left( \frac{112}{219} \right) \times 100\%$
Let's perform the calculation:
$\frac{112}{219} \approx 0.5114155...$
Percentage of students in Sec A $\approx 0.5114155... \times 100\%$
Percentage of students in Sec A $\approx 51.14155...\%$
The question asks us to round the percentage to one decimal place. Rounding $51.14155...\%$ to one decimal place gives $51.1\%$.
Based on the calculation using the provided table data, the percentage of students in Section A is approximately 51.1%.
Among the given options, option 2 is 51.4%.
| Metric | Calculation | Value |
|---|---|---|
| Total students in Sec A | $28 + 14 + 6 + 64$ | $112$ |
| Total students in Sec B | $23 + 12 + 17 + 55$ | $107$ |
| Total students (Sec A + Sec B) | $112 + 107$ | $219$ |
| Percentage of students in Sec A | $\left( \frac{112}{219} \right) \times 100\%$ | $\approx 51.14\%$ |
| Percentage rounded to one decimal | Rounding $51.14\%$ to one decimal | $51.1\%$ |
A percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, '%', or the abbreviations 'pct.', 'pct'. Sometimes the abbreviation 'pc' is also used. Percentages are used to express how large one quantity is in relation to another quantity; the second quantity is the base or the whole, which is considered as 100%.
In this problem, the 'whole' is the total number of students in both sections, and the 'part' is the number of students in Section A. We calculate what percentage the 'part' is of the 'whole'.
The formula for calculating percentage is universally applied:
Percentage = $\left( \frac{\text{Part}}{\text{Whole}} \right) \times 100\%$
Rounding is necessary when the result of a calculation has more decimal places than required by the question. Rounding to one decimal place means keeping one digit after the decimal point and adjusting it based on the value of the second digit:
For example, 51.14 rounded to one decimal place is 51.1 because the second digit (4) is less than 5. If the number was 51.16, it would round to 51.2.
In south, what is the percentage of seats won by party A (round to one decimal)?
Direction: Study the table given below and answer the following question.
City | Population | Literate | Illiterate | % of literates |
A | 200 | 150 | 50 | - |
B | - | 200 | 100 | 66.6 |
C | 150 | 50 | 100 | - |
D | 120 | - | 90 | 25 |
Based on the given data, the percentage of literates in city A is _________.
Student/Subject | P | C | B | M |
W | 70 | 90 | 50 | 85 |
X | 55 | 80 | 95 | 60 |
Y | 60 | 20 | 90 | 40 |
Z | 90 | 80 | 40 | 65 |
The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M, with the maximum marks in each subject being 100.
The average marks of the four students in P and C together (round to one decimal) is:
The average salary per year during period 2001 – 2006 is:
Based on the given data, the percentage of literates in City C is ______ (round to one decimal).
Based on the given data, the total number of candidates elected is _______.
Direction: Study the table given below and answer the following question.
City | Population | Literate | Illiterate | % of literates |
A | 200 | 150 | 50 | - |
B | - | 200 | 100 | 66.6 |
C | 150 | 50 | 100 | - |
D | 120 | - | 90 | 25 |
Based on the given data, the total percentage of literates in the four cities together, round to one decimal, is ______.
The average expenditure per year during the period 2001-2006 is _____ (round off the nearest integer).
What is the total number of students in both, section A and B?
In which year did Bhutan’s rice production decrease for the first time?
Table shows income (in Rs.) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38000 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
The table given below shows the GDP of two countries in different five years.
| Country | ||
| Years | A | B |
| Y1 | 175 | 285 |
| Y2 | 200 | 300 |
| Y3 | 150 | 125 |
| Y4 | 75 | 85 |
| Y5 | 50 | 95 |
K1 = The value of average GDP of country A in all the 5 years.
K2 = The value of average GDP of country B in all the 5 years.
What is the value of (K1 + K2)?
Study the Table Properly and answer by interpreting the data
The table shows the percentage population of five districts in a state below poverty line and the proportion of males and females.
| District | Percentage of population below poverty level | Proportion of Male and Female | |
| Below poverty line (M:F) | Above poverty Line (M:F) | ||
| D1 | 15 | 2 : 3 | 3 : 2 |
| D2 | 18 | 3 : 4 | 7 : 5 |
| D3 | 20 | 2 : 5 | 3 : 4 |
| D4 | 25 | 5 : 2 | 4 : 3 |
| D5 | 12 | 3 : 7 | 2 : 7 |
If the total population in the district D3 is 40,000, then what is the population of below poverty line in the district D3, ?
The table given below shows the marks obtained by 4 students in 5 subjects. The maximum marks of each subject is 100.
Subjects | Students | |||
P1 | P2 | P3 | P4 | |
S1 | 89 | 100 | 92 | 91 |
S2 | 62 | 52 | 72 | 37 |
S3 | 57 | 55 | 70 | 65 |
S4 | 76 | 85 | 76 | 58 |
S5 | 85 | 70 | 66 | 62 |
What is the total percent marks of P4?
The data given below shows the number of people who have saved a certain amount of money.
Savings (in Rs.) | Number of people |
5 | 1 |
15 | 3 |
20 | 4 |
25 | 2 |
30 | 1 |
35 | 1 |
40 | 2 |
What is the mode of the given data?