For any polygon, the internal angle and its corresponding external angle at a vertex add up to $180^\circ$. This is because they form a linear pair.
The relationship is:
Internal Angle + External Angle = $180^\circ$
The question states that the external angle of the regular polygon is $72^\circ$.
Using the property above, we can find the internal angle:
Internal Angle = $180^\circ$ - External Angle
Substitute the given value:
Internal Angle = $180^\circ - 72^\circ$
Internal Angle = $108^\circ$
Therefore, the internal angle of the regular polygon is $108^\circ$.
ABCDEF is a regular hexagon. Side of the hexagon is 36 cm. What is the area of the triangle AOB ?
If ∆ABC ~ ∆DEF, and BC = 4 cm, EF = 5 cm and the area of triangle ABC = 80 cm 2, then the area of the triangle DEF is:
If Δ ABC is right angled at B, AB = 12 cm and ∠CAB = 60°, determine the length of BC.
If ΔABC and ΔDEF are congruent triangles, then which of the following is FALSE?
D and E are points on the sides AB and AC, respectively, of ΔABC such that DE is parallel to BC and AD ∶ DB = 7 ∶ 9. If CD and BE intersect each other at F. then find the ratio of areas of ΔDEF and ΔCBF.