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Question

If the sum of the interior angles of a regular polygon is equal to four times the sum of its exterior angles, then what is the number of diagonals in the polygon?

This question was previously asked in
RRB NTPC 2024 CBT 1 Question Paper (28-Aug-2025) (Shift 3)
The correct answer is
35

Calculating Polygon Diagonals Based on Angle Sums

This problem requires us to find the number of diagonals in a regular polygon given a relationship between its interior and exterior angle sums.

Step 1: Relate Interior and Exterior Angle Sums

Let $n$ be the number of sides of the regular polygon.

  • The sum of the interior angles of an $n$-sided polygon is given by the formula: $ \text{Sum}_{\text{interior}} = (n-2) \times 180^\circ $.
  • The sum of the exterior angles of any convex polygon is constant: $ \text{Sum}_{\text{exterior}} = 360^\circ $.

The problem states that the sum of the interior angles is four times the sum of its exterior angles:

$ (n-2) \times 180^\circ = 4 \times 360^\circ $

Step 2: Solve for the Number of Sides (n)

Simplify the equation:

$ (n-2) \times 180 = 1440 $

Divide both sides by 180:

$ n-2 = \frac{1440}{180} $ $ n-2 = 8 $

Add 2 to both sides:

$ n = 8 + 2 $ $ n = 10 $

The polygon has 10 sides.

Step 3: Calculate the Number of Diagonals

The formula for the number of diagonals ($D$) in an $n$-sided polygon is:

$ D = \frac{n(n-3)}{2} $

Substitute $n=10$ into the formula:

$ D = \frac{10(10-3)}{2} $ $ D = \frac{10 \times 7}{2} $ $ D = \frac{70}{2} $ $ D = 35 $

Therefore, the polygon has 35 diagonals.

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Important Questions from Geometry

  1. ABCDEF is a regular hexagon. Side of the hexagon is 36 cm. What is the area of the triangle AOB ?

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