The question asks us to find the number of values for the variable $\theta$ that satisfy the given equation:
$$ \sin^2 \theta + \cos^2 \theta - 1 = 0 $$
To solve this, we need to recall a fundamental identity in trigonometry.
One of the most basic and important trigonometric identities is the Pythagorean identity, which states:
$$ \sin^2 \theta + \cos^2 \theta = 1 $$
This identity holds true for any real value of $\theta$.
Now, let's substitute the value of $\sin^2 \theta + \cos^2 \theta$ from the identity into the given equation:
Original Equation: $ \sin^2 \theta + \cos^2 \theta - 1 = 0 $
Substitute using the identity: $ (1) - 1 = 0 $
Simplify the result: $ 0 = 0 $
The equation simplifies to $0 = 0$. This is a true statement, regardless of the specific value chosen for $\theta$. This means the original expression is not an equation with a limited number of solutions, but rather a trigonometric identity that is true for all possible values of $\theta$.
Because the equation $ \sin^2 \theta + \cos^2 \theta - 1 = 0 $ simplifies to $0 = 0$, which is always true, the equation is satisfied by infinitely many values of $\theta$.
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