Evaluate the following. $$\frac{5\cos^2 120^\circ + 4\sec^2 30^\circ - \tan^2 135^\circ} {\sin^2 30^\circ + \cos^2 30^\circ}$$
The question asks us to evaluate the expression: $$ \frac{5\cos^2 120^\circ + 4\sec^2 30^\circ - \tan^2 135^\circ} {\sin^2 30^\circ + \cos^2 30^\circ} $$ To solve this, we need to find the values of the trigonometric functions at the given angles and substitute them into the expression.
First, let's find the values for each trigonometric function required:
Now substitute these squared values back into the original expression:
$$ \frac{5\left(\frac{1}{4}\right) + 4\left(\frac{4}{3}\right) - 1} {\left(\frac{1}{4}\right) + \left(\frac{3}{4}\right)} $$Let's simplify the numerator first:
Numerator = $5 \times \frac{1}{4} + 4 \times \frac{4}{3} - 1$
Numerator = $\frac{5}{4} + \frac{16}{3} - 1$
To add these fractions, we find a common denominator, which is 12:
Numerator = $\frac{5 \times 3}{4 \times 3} + \frac{16 \times 4}{3 \times 4} - \frac{1 \times 12}{1 \times 12}$
Numerator = $\frac{15}{12} + \frac{64}{12} - \frac{12}{12}$
Numerator = $\frac{15 + 64 - 12}{12}$
Numerator = $\frac{79 - 12}{12}$
Numerator = $\frac{67}{12}$
Now, let's simplify the denominator:
Denominator = $\sin^2 30^\circ + \cos^2 30^\circ$
Using the trigonometric identity $\sin^2 \theta + \cos^2 \theta = 1$, we know that:
Denominator = $\frac{1}{4} + \frac{3}{4} = \frac{1+3}{4} = \frac{4}{4} = 1$.
Alternatively, substituting the calculated values:
Denominator = $\frac{1}{4} + \frac{3}{4} = 1$.
Now, divide the simplified numerator by the simplified denominator:
$$ \frac{\text{Numerator}}{\text{Denominator}} = \frac{67/12}{1} $$ $$ = \frac{67}{12} $$Thus, the value of the expression is $\frac{67}{12}$.
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