(A) depends on r, where r is the magnitude of position vector $\vec{r}$
(B) depends on the angle between the position vector $\vec{r}$ and the dipole moment vector $\vec{p}$
(C) falls off at long distances, as $1/r^2$
(D) does not depend upon the distance separating the charges
Choose the correct answer from the options given below:
An electric dipole consists of two equal and opposite charges separated by a small distance. The electric potential at any point in space due to an electric dipole depends on several factors related to the dipole's properties and the observation point's location.
The electric potential ($V$) at a point P, located at a distance $r$ from the center of the dipole, is given by the formula:
$ V = \frac{1}{4\pi\epsilon_0} \frac{\vec{p} \cdot \vec{r}}{r^3} $
This can also be expressed using the angle $\theta$ between the dipole moment vector ($\vec{p}$) and the position vector ($\vec{r}$):
$ V = \frac{1}{4\pi\epsilon_0} \frac{p \cos\theta}{r^2} $
Here,
Statement (A) says the potential depends on $r$, the magnitude of the position vector. Looking at the formula $V = \frac{1}{4\pi\epsilon_0} \frac{p \cos\theta}{r^2}$, it's clear that $V$ is inversely proportional to $r^2$. Therefore, the electric potential due to a dipole **depends on $r$**. Statement (A) is correct.
Statement (B) states that the potential depends on the angle between the position vector $\vec{r}$ and the dipole moment vector $\vec{p}$. The term $\cos\theta$ in the formula $V = \frac{1}{4\pi\epsilon_0} \frac{p \cos\theta}{r^2}$ explicitly shows this dependence. The potential varies with the angle $\theta$; for example, it's maximum along the axis ($\theta=0^\circ$) and zero on the perpendicular bisector ($\theta=90^\circ$). Statement (B) is correct.
Statement (C) claims the potential falls off as $1/r^2$ at long distances. As observed from the formula $V \propto \frac{1}{r^2}$, the potential decreases with the square of the distance from the dipole. This is characteristic of a dipole field at large distances. Statement (C) is correct.
Statement (D) claims the potential does not depend on the distance separating the charges. The dipole moment $p$ is defined as the product of the magnitude of one charge ($q$) and the distance ($d$) separating the two charges ($p = qd$). Since the potential $V$ is directly proportional to $p$, it inherently **depends on the distance separating the charges** ($d$). Therefore, statement (D) is incorrect.
Based on the analysis of the formula and the behavior of electric potential due to a dipole:
Therefore, the correct combination of statements is (A), (B), and (C).
Two charged particles, placed at a distance d apart in vacuum, exert a force F on each other. Now, each of the charges is doubled. To keep the force unchanged, the distance between the charges should be changed to:
When a slab of insulating material 4 mm thick is introduced between the plates of a parallel plate capacitor of separation 4 mm, it is found that the distance between the plates has to be increased by 3.2 mm to restore the capacity to its original value. The dielectric constant of the material is:
Match List - I with List - II.
| List - I | List - II |
|---|---|
| (A) Electric Field | (I) [LTA] |
| (B) Electric Flux | (II) [L2] |
| (C) Electric Dipole Moment | (III) [ML3T−3A−1] |
| (D) Area Vector Element | (IV) [MLT−3A−1] |
Choose the correct answer from the options given below:
A thin metallic spherical shell contains a charge +10 μC on it. A point charge +2 μC is placed at the centre of the shell and another charge +5 μC is placed outside it as shown. The force on the charge +2 μC at the centre is:

In the figure, an α-particle moves a distance l in a uniform electric field E as shown. Does the Electric Field do a positive or a negative work on the α-particle? Does the electric potential energy of the α-particle increase or decrease?
