This problem involves finding the number of sides ($n$) of a regular polygon based on the difference between its interior and exterior angles at a vertex.
For a regular polygon with $n$ sides:
We are given that the difference between the interior and exterior angles is $160^\circ$. So:
$I - E = 160^\circ$Substitute the expression for $I$ ($I = 180^\circ - E$) into the equation:
$(180^\circ - E) - E = 160^\circ$ $180^\circ - 2E = 160^\circ$Now, solve for the exterior angle $E$:
$2E = 180^\circ - 160^\circ$ $2E = 20^\circ$ $E = \frac{20^\circ}{2}$ $E = 10^\circ$Finally, use the formula for the exterior angle to find the number of sides ($n$):
$E = \frac{360^\circ}{n}$ $10^\circ = \frac{360^\circ}{n}$Rearrange the formula to solve for $n$:
$n = \frac{360^\circ}{10^\circ}$ $n = 36$Therefore, the regular polygon has 36 sides.
ABCDEF is a regular hexagon. Side of the hexagon is 36 cm. What is the area of the triangle AOB ?
If ∆ABC ~ ∆DEF, and BC = 4 cm, EF = 5 cm and the area of triangle ABC = 80 cm 2, then the area of the triangle DEF is:
If Δ ABC is right angled at B, AB = 12 cm and ∠CAB = 60°, determine the length of BC.
If ΔABC and ΔDEF are congruent triangles, then which of the following is FALSE?
D and E are points on the sides AB and AC, respectively, of ΔABC such that DE is parallel to BC and AD ∶ DB = 7 ∶ 9. If CD and BE intersect each other at F. then find the ratio of areas of ΔDEF and ΔCBF.