The core principle is that the volume of the material remains constant when a solid is melted and recast. Therefore, the volume of the copper sphere is equal to the volume of the wire (which is a cylinder).
\(V_s = \frac{4}{3} \pi r_s^3\)
\(V_s = \frac{4}{3} \pi (3 \text{ cm})^3 = \frac{4}{3} \pi (27 \text{ cm}^3) = 36 \pi \text{ cm}^3\)
\(V_w = \pi r_w^2 h\)
where '\(h\)' is the length of the wire.\(V_w = \pi (0.25 \text{ cm})^2 h = \pi (0.0625 \text{ cm}^2) h\)
\(V_s = V_w\)
\(36 \pi \text{ cm}^3 = \pi (0.0625 \text{ cm}^2) h\)
\(36 \text{ cm}^3 = 0.0625 \text{ cm}^2 \times h\)
\(h = \frac{36 \text{ cm}^3}{0.0625 \text{ cm}^2}\)
\(h = 576 \text{ cm}\)
\(h = \frac{576}{100} \text{ m} = 5.76 \text{ m}\)
The length of the wire is 5.76 m.
Find the total surface area of a closed cylinder having a base radius of 70 m and a height of 110 m. [Use π = \(22\over7\)]
Which of the following is a geometrical figure with a three-dimensional geometry that has eight vertices and six rectangular faces?
The diameter of the base and slant height of a right circular cone are 30 cm and 113 cm, respectively. Find the volume (in cm³) of the given cone.
(Use $\pi = \frac{22}{7}$)