\(\frac{7}{3}\) cm
The problem asks for the increase in water level within a cylinder when a sphere is fully submerged. This water level rise is equivalent to the volume of the sphere divided by the cross-sectional area of the cylinder.
The diameter of the sphere is given as 14 cm.
The formula for the volume of a sphere is:
\(V_{\text{sphere}} = \frac{4}{3} \pi r^3\)
Substitute the sphere's radius into the formula:
\(V_{\text{sphere}} = \frac{4}{3} \pi (7 \text{ cm})^3 = \frac{4}{3} \pi (343) \text{ cm}^3\)
The radius of the cylindrical vessel (\(R\)) is given as 14 cm.
When the sphere is completely submerged, the volume of water displaced equals the sphere's volume. This displaced volume causes the water level in the cylinder to rise.
The volume of the water rise (\(V_{\text{rise}}\)) forms a cylinder with radius \(R\) and height \(h\) (the water level rise).
The formula for the volume of the water rise is:
\(V_{\text{rise}} = \pi R^2 h\)
Substitute the cylinder's radius:
\(V_{\text{rise}} = \pi (14 \text{ cm})^2 h = \pi (196) h \text{ cm}^3\)
The volume of the submerged sphere must equal the volume of the water rise in the cylinder:
\(V_{\text{sphere}} = V_{\text{rise}}\)
\(\frac{4}{3} \pi (343) \text{ cm}^3 = \pi (196) h \text{ cm}^3\)
To find the height (\(h\)), we can cancel \(\pi\) from both sides and rearrange the equation:
\(\frac{4}{3} \times 343 = 196 h\)
\(h = \frac{4 \times 343}{3 \times 196}\)
Simplify the expression:
The water level rise is calculated to be \(\frac{7}{3}\) cm.
Find the total surface area of a closed cylinder having a base radius of 70 m and a height of 110 m. [Use π = \(22\over7\)]
Which of the following is a geometrical figure with a three-dimensional geometry that has eight vertices and six rectangular faces?
The diameter of the base and slant height of a right circular cone are 30 cm and 113 cm, respectively. Find the volume (in cm³) of the given cone.
(Use $\pi = \frac{22}{7}$)