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Question

The cost of 2 pencil, 4 pens and 8 erasers is Rs. 12 and the cost of 8 pens, 10 pencils and 4 erasers is Rs. 36. How much will 3 pencils, 3 pens and 3 erasers cost?

This question was previously asked in
RRB NTPC 2015 CBT 1 Question Paper PDF (2-Apr-2016) (Shift 3)
The correct answer is

Rs. 12

Let the cost of a pencil = x, a pen = y and an eraser = z (in Rs.).

2x + 4y + 8z = 12 ...(1)
10x + 8y + 4z = 36 ...(2)

Adding (1) and (2):
12x + 12y + 12z = 48
x + y + z = 4

Cost of 3 pencils, 3 pens and 3 erasers = 3(x + y + z)
= 3 × 4
= Rs. 12

Check: the two equations together contain 12 of each item costing Rs. 48, so one set costs Rs. 4 and three sets cost Rs. 12.

Hence, Rs. 12.

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Important Questions from Linear Equation in 2 or more Variables

  1. If \(3x+6y+9z = \dfrac{20}{3}, 6x+9y + 3z = \dfrac{17}{3}\)  and  \(18x+ 27y - z = \dfrac{113}{9}\) , then what is the value of  \(75x+113y \ ?\)

  2. If the system of equations 2x - 3y - 3 and -4x + qy - p/2 is inconsistent which of the following cannot be the value of p ?

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  4. Simplify: 7x + 3x(x – 4) = ?

    A. 10x + 12

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