Ram has ₹1000 in the denomination of ₹10, ₹20 and ₹5 notes. If the number of ₹10 notes is 16 more than that of ₹20 notes and the number of ₹5 notes is twice the number of ₹20 notes, find the total number of notes that Ram has.
100
Let the number of ₹20 notes be \(x\).
Then the number of ₹10 notes \(= x + 16\), and the number of ₹5 notes \(= 2x\).
Total value: \(20x + 10(x + 16) + 5(2x) = 1000\).
Expanding: \(20x + 10x + 160 + 10x = 1000\).
\(40x = 840\), so \(x = 21\).
Number of ₹20 notes = 21, ₹10 notes = 37, ₹5 notes = 42.
Total number of notes \(= 21 + 37 + 42 = 100\).
Hence, Ram has a total of 100 notes.
Similar Questions
- Two numbers are such that the sum of $\frac{1}{3}$ of the first number and $\frac{1}{2}$ of the second number is 8. The sum of $\frac{1}{5}$ of the first number and $\frac{1}{6}$ of the second number is 4. What is the largest of the two numbers?
- If $2\text{x} + \text{y} = 15$, $\text{y} + 2\text{z} = 17$ and $\text{x} + 2\text{y} = 9$, then the value of $4\text{x} + 3\text{y} + \text{z} = ?$
An amount of ₹120 is paid using ₹10, ₹5 and ₹2 coins. If the number of coins of ₹10 and ₹2 are interchanged, then the amount becomes ₹304. If the number of ₹5 and ₹2 coins are interchanged, then the amount is ₹165. How many ₹2 coins are used in the payment of ₹120?
Important Questions from Linear Equation in 2 or more Variables
If \(3x+6y+9z = \dfrac{20}{3}, 6x+9y + 3z = \dfrac{17}{3}\) and \(18x+ 27y - z = \dfrac{113}{9}\) , then what is the value of \(75x+113y \ ?\)
If the system of equations 2x - 3y - 3 and -4x + qy - p/2 is inconsistent which of the following cannot be the value of p ?
If \(4x + \dfrac{6}{y}= 15 \) and \(6x - \dfrac{8}{y} = 14\) , then the value of p in y = px - 2 is :
Simplify: 7x + 3x(x – 4) = ?
A. 10x + 12
B. 10x – 12
C. 3x2 + 5x
D. 3x2 – 5xIf 5x + y = 17 and xy = 6, then what is the value of 125x3 + y3 ?
