The question presents two cobalt coordination complexes:
We need to determine the type of isomerism they exhibit.
Observe the components of each complex:
The key difference is the exchange of a ligand within the coordination sphere ($Cl^-$) and the counter ion ($NO_2^-$). Specifically, the $NO_2$ group acts as the counter ion in the first complex but as a ligand in the second complex. Conversely, a $Cl^-$ ion acts as a ligand in the first complex and is the counter ion in the second.
Ionization isomers are coordination compounds that have the same molecular formula but differ in the ions present inside and outside the coordination sphere. The ion outside the coordination sphere in one isomer acts as a ligand within the coordination sphere in the other isomer, and vice versa.
Based on the analysis:
The nitrite ion ($NO_2^-$), which is the counter ion in Complex 1, is a ligand in Complex 2. The chloride ion ($Cl^-$), which is a ligand in Complex 1, is the counter ion in Complex 2. This direct exchange between a ligand and the counter ion defines ionization isomerism.
Therefore, the complexes are ionization isomers.
Consider the figure given below, where M is a metal and L is a monodentate ligand. The $\sigma$-bonding ligand group orbital (LGO) having same symmetry with $d_{z^2}$ orbital of M in the octahedral coordination geometry is
Among the given platinum(II) complexes, the one that is thermally the most unstable is