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Question

The complexes $[Co(H_2O)_4Cl_2]NO_2$ and $[Co(H_2O)_4Cl(NO_2)]Cl$ are

The correct answer is
ionization isomers

Understanding Cobalt Complex Isomerism

The question presents two cobalt coordination complexes:

  • Complex 1: $[Co(H_2O)_4Cl_2]NO_2$
  • Complex 2: $[Co(H_2O)_4Cl(NO_2)]Cl$

We need to determine the type of isomerism they exhibit.

Analyzing the Complex Structures

Observe the components of each complex:

  • Coordination Sphere: In both complexes, the coordination sphere contains one Cobalt (Co) ion, four water molecules ($H_2O$), and one chloride ion ($Cl^-$).
  • Counter Ion: The ion outside the coordination sphere differs.
    • In Complex 1, the counter ion is the nitrite ion ($NO_2^-$).
    • In Complex 2, the counter ion is the chloride ion ($Cl^-$).

The key difference is the exchange of a ligand within the coordination sphere ($Cl^-$) and the counter ion ($NO_2^-$). Specifically, the $NO_2$ group acts as the counter ion in the first complex but as a ligand in the second complex. Conversely, a $Cl^-$ ion acts as a ligand in the first complex and is the counter ion in the second.

Defining Ionization Isomers

Ionization isomers are coordination compounds that have the same molecular formula but differ in the ions present inside and outside the coordination sphere. The ion outside the coordination sphere in one isomer acts as a ligand within the coordination sphere in the other isomer, and vice versa.

Conclusion on Isomer Type

Based on the analysis:

  • Complex 1: $[Co(H_2O)_4Cl_2]NO_2$ (Nitrite ion is the counter ion)
  • Complex 2: $[Co(H_2O)_4Cl(NO_2)]Cl$ (Chloride ion is the counter ion, Nitrite ion is a ligand)

The nitrite ion ($NO_2^-$), which is the counter ion in Complex 1, is a ligand in Complex 2. The chloride ion ($Cl^-$), which is a ligand in Complex 1, is the counter ion in Complex 2. This direct exchange between a ligand and the counter ion defines ionization isomerism.

Therefore, the complexes are ionization isomers.

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Important Questions from Coordination Chemistry

  1. An aqueous solution of $Co(ClO_4)_2 \cdot 6H_2O$ is light pink in colour. Addition of conc. HCl results in an intense blue coloured solution due to the formation of a new species. The new species among the following is


    [Given: Atomic number of Co = 27]

  2. Among the following, the compound with the lowest CO stretching frequency is
  3. The rates of substitution for the following reaction vary with L in the order 

  4. Identify X in the reaction, $[Pt(NH_3)_4]^{2+} + 2 HCl \rightarrow X$
  5. Among the following octahedral complexes, the one that has the highest enthalpy of hydration is
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