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Question

The complex that exists as a pair of enantiomers is

The correct answer is
$[Co(H_2NCH_2CH_2NH_2)_3]^{3+}$

To determine which complex exists as a pair of enantiomers, we need to identify the chiral complex among the given options. Chirality in coordination complexes arises from the absence of symmetry elements like a plane of symmetry (σ) or a center of symmetry (i).

Chirality Analysis of Complexes

  • Option 1: $trans-[Co(H_2NCH_2CH_2NH_2)_2Cl_2]^+$
    • This is an octahedral complex of the type [MA2B2], where A is the bidentate ligand ethylenediamine (en) and B is the monodentate ligand chloride (Cl).
    • The trans isomer, with the two Cl- ligands opposite each other, possesses a plane of symmetry.
    • Therefore, this complex is achiral.
  • Option 2: $cis-[Co(NH_3)_4Cl_2]^+$
    • This is an octahedral complex of the type [MA4B2], where A is ammonia (NH3) and B is chloride (Cl).
    • The cis isomer, with the two Cl- ligands adjacent, has a plane of symmetry passing through the metal and the two Cl ligands.
    • Therefore, this complex is achiral.
  • Option 3: $[Pt(PPh_3)(Cl)(Br)(CH_3)]^-$
    • This is a square planar complex with four different monodentate ligands: PPh3, Cl, Br, and CH3.
    • A square planar complex with four distinct ligands is typically chiral.
  • Option 4: $[Co(H_2NCH_2CH_2NH_2)_3]^{3+}$
    • This is an octahedral complex of the type [M(AA)3]n+, where AA is the symmetrical bidentate ligand ethylenediamine (en).
    • Complexes of the type [M(AA)3]n+, with symmetrical bidentate ligands like ethylenediamine, lack any plane or center of symmetry.
    • The arrangement of the three ethylenediamine ligands around the central cobalt ion creates a chiral structure.
    • Therefore, this complex exists as a pair of enantiomers.

Conclusion on Enantiomers

The complex that exhibits chirality and exists as a pair of enantiomers is the one lacking symmetry elements. Based on the analysis, the complex $[Co(H_2NCH_2CH_2NH_2)_3]^{3+}$ fits this criterion.

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Important Questions from Coordination Chemistry

  1. An aqueous solution of $Co(ClO_4)_2 \cdot 6H_2O$ is light pink in colour. Addition of conc. HCl results in an intense blue coloured solution due to the formation of a new species. The new species among the following is


    [Given: Atomic number of Co = 27]

  2. Among the following, the compound with the lowest CO stretching frequency is
  3. The rates of substitution for the following reaction vary with L in the order 

  4. Identify X in the reaction, $[Pt(NH_3)_4]^{2+} + 2 HCl \rightarrow X$
  5. Among the following octahedral complexes, the one that has the highest enthalpy of hydration is
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