The Boolean expression \(AC+B\bar{C}\) is equivalent to :
\(ABC+\bar{A}B\bar{C}+AB\bar{C}+A\bar{B}C\)
To determine the equivalence of the Boolean expression \(AC + B\bar{C}\), we need to employ Boolean algebra rules to simplify and analyze the given options.
Conclusion: After analyzing, the option that matches the original Boolean expression \(AC + B\bar{C}\) in logical equivalence is Option 4: \(ABC + \bar{A}B\bar{C} + AB\bar{C} + A\bar{B}C\). This option expands to handle the truth table equivalent conditions for the given expression.
Consider the following expressions :
(a) Y = f(A, B, C, D) = Σ (1, 2, 4, 7, 8, 11, 13, 14)
(b) Y = f(A, B, C, D) = Σ (3, 5, 7, 10, 11, 12, 13, 14)
(c) Y = f(A, B, C, D) = Π (0, 3, 5, 6, 9, 10, 12, 15)
(d) Y = f(A, B, C, D) = Π (0, 1, 2, 4, 5, 8, 9, 15)
Which of the above expressions are equivalent to the expression Y = A⊕B⊕C⊕D ?
The output of the circuit is given by :

In Boolean algebra, the term sum of products means
The value of \(\rm \overline{A+B}\) is :
The Boolean function Y = AB + CD is to be realized using only two-input NAND gates. The minimum number of gates required are:
The minimum number of 2-input NAND gates required to realize the logic function $Y = AB + \bar A \bar B$ is