The bar chart given below shows the number of boys and girls in 5 schools. If the number of boys in school S6 are 30 percent more than the number of girls in school S1, then number of girls in schools S3 and S4 is what percentage of number of boys in schools S6 and S1 ? (correct to two decimal places)
118.92
Given:
Boys(S6) = Girls(S1) + 0.3[ Girls(S1)]
Girls(S1) = 500
Solution:
Boys(S6) = 500 + 0.3(500) = 650
Girls(S3 + S4) = m x Boys(S6 + S1)
From the graph,
1800 + 400 = m x (650 + 1200)
2200 = m x (1850)
m = 220/185 = 1.1892
m% = 118.92%
Hence, the number of girls in schools S3 and S4 is 118.92% of the number of boys in schools S6 and S1.
Confusion point - If the number of boys in school S6 are 30 percent more than the number of girls in school S1 (Clearly mentioned in the question) , S6 is not directly given we have to calculate the value of S6 From S1, and by the given relation between them.
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