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Question

The average of five positive numbers is 56. If the first number is three-fourth of the sum of the last four numbers, then the average of the last four numbers is:

This question was previously asked in
SSC CGL 2019 (Tier 2) GS Finance & Economics Previous Year Paper (17-Nov-2020)
The correct answer is

40

Understanding the Average of Positive Numbers

The problem involves the concept of average, specifically the average of five positive numbers. The average is calculated by dividing the sum of the numbers by the count of the numbers.

We are given that the average of five positive numbers is 56. Let the five positive numbers be \(n_1, n_2, n_3, n_4,\) and \(n_5\).

The formula for the average is:

$$\text{Average} = \frac{\text{Sum of numbers}}{\text{Count of numbers}}$$

In this case, the sum of the five numbers is \(n_1 + n_2 + n_3 + n_4 + n_5\), and the count is 5. The average is given as 56.

So, we can write the equation:

$$\frac{n_1 + n_2 + n_3 + n_4 + n_5}{5} = 56$$

Calculating the Total Sum of Five Positive Numbers

From the average formula, we can find the sum of the five numbers:

$$\text{Sum of numbers} = \text{Average} \times \text{Count of numbers}$$

Sum of the five numbers \( = 56 \times 5 \)

Sum of the five numbers \( = 280 \)

So, \(n_1 + n_2 + n_3 + n_4 + n_5 = 280\).

Relating the First Number to the Sum of the Last Four Numbers

The question gives a relationship between the first number and the sum of the last four numbers. It states that the first number (\(n_1\)) is three-fourth of the sum of the last four numbers (\(n_2 + n_3 + n_4 + n_5\)).

Let \(S_4\) be the sum of the last four numbers. So, \(S_4 = n_2 + n_3 + n_4 + n_5\).

According to the problem statement:

$$n_1 = \frac{3}{4} \times (n_2 + n_3 + n_4 + n_5)$$

Substituting \(S_4\):

$$n_1 = \frac{3}{4} S_4$$

Finding the Sum of the Last Four Numbers

We know that the total sum of the five numbers is 280:

$$n_1 + (n_2 + n_3 + n_4 + n_5) = 280$$

Substituting \(S_4 = n_2 + n_3 + n_4 + n_5\), we get:

$$n_1 + S_4 = 280$$

Now, substitute the relationship \(n_1 = \frac{3}{4} S_4\) into this equation:

$$\frac{3}{4} S_4 + S_4 = 280$$

Combine the terms involving \(S_4\):

$$\left(\frac{3}{4} + 1\right) S_4 = 280$$

$$\left(\frac{3}{4} + \frac{4}{4}\right) S_4 = 280$$

$$\frac{7}{4} S_4 = 280$$

To find \(S_4\), multiply both sides by \(\frac{4}{7}\):

$$S_4 = 280 \times \frac{4}{7}$$

$$S_4 = \frac{280}{7} \times 4$$

$$S_4 = 40 \times 4$$

$$S_4 = 160$$

So, the sum of the last four numbers is 160.

Calculating the Average of the Last Four Numbers

The question asks for the average of the last four numbers. The last four numbers are \(n_2, n_3, n_4,\) and \(n_5\), and their sum is \(S_4 = 160\). The count of these numbers is 4.

The average of the last four numbers is:

$$\text{Average of last four numbers} = \frac{\text{Sum of last four numbers}}{\text{Count of last four numbers}}$$

$$\text{Average of last four numbers} = \frac{S_4}{4}$$

$$\text{Average of last four numbers} = \frac{160}{4}$$

$$\text{Average of last four numbers} = 40$$

Therefore, the average of the last four numbers is 40.

Let's check the options:

  • Option 1: 50
  • Option 2: 35
  • Option 3: 30
  • Option 4: 40

Our calculated average matches Option 4.

Step-by-Step Solution Summary

  1. Write down the given information: Average of 5 numbers = 56.
  2. Calculate the total sum of the 5 numbers: Sum = Average × Count = \(56 \times 5 = 280\).
  3. Identify the relationship between the first number (\(n_1\)) and the sum of the last four numbers (\(S_4\)): \(n_1 = \frac{3}{4} S_4\).
  4. Write the total sum in terms of \(n_1\) and \(S_4\): \(n_1 + S_4 = 280\).
  5. Substitute the relationship from step 3 into the equation from step 4: \(\frac{3}{4} S_4 + S_4 = 280\).
  6. Solve for \(S_4\): \(\frac{7}{4} S_4 = 280 \implies S_4 = 280 \times \frac{4}{7} = 160\).
  7. Calculate the average of the last four numbers: Average = \(\frac{S_4}{4} = \frac{160}{4} = 40\).
Concept Formula / Relationship Value
Average of 5 numbers \(\frac{\text{Sum of 5 numbers}}{5}\) 56
Sum of 5 numbers Average × Count \(56 \times 5 = 280\)
Relationship \(n_1\) and \(S_4\) \(n_1 = \frac{3}{4} S_4\) -
Total Sum \(n_1 + S_4\) 280
Equation for \(S_4\) \(\frac{3}{4} S_4 + S_4 = 280\) -
Sum of last 4 numbers (\(S_4\)) Solved from equation 160
Average of last 4 numbers \(\frac{S_4}{4}\) \(\frac{160}{4} = 40\)

Revision Table: Average and Sum Concepts

Term Definition How it's used here
Average (Arithmetic Mean) Sum of values divided by the count of values. Given for 5 numbers, calculated for 4 numbers.
Sum The total result of adding numbers together. Calculated for 5 numbers and for the last 4 numbers.
Positive Numbers Numbers greater than zero. The context of the problem involves positive numbers.

Additional Information: Solving Average Word Problems

Solving average word problems often involves translating the given information into algebraic equations. Key steps usually include:

  • Identifying the total sum from the given average and count.
  • Using any given relationships between numbers to form additional equations.
  • Substituting one equation into another to solve for unknown quantities (like the sum of a subset of numbers).
  • Finally, calculating the requested average using the sum and count of the relevant numbers.

Understanding how the sum, average, and count relate to each other is fundamental to solving these types of quantitative aptitude problems.

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Similar Questions

  1. 24 students collected money for donation. The average contribution was Rs. 50. Later on, their teacher also contributed some money. Now the average contribution is Rs. 56. The teacher’s contribution is:

  2. The average of six numbers is 3.52. The average of two of them is 3.7, while the average of other two is 2.5. What is the average of the remaining two?

  3. A student‘s marks were wrongly entered as 65 instead of 45. Due to this, the average marks for the class got increased by 1/3. The number of students in the class is:

  4. The average working hours per month of the staff aged over 50 years in a factory were 160 and that of the staff aged under 50 years were 210. The mean working hour per month of all the staff was 200. The ratio of the number of the staff aged over 50 to that the staff aged under 50 is:

  5. For a group of 100 students, the mean and standard deviation of scores were found to be 30 and 5 respectively. Later on it was discovered that the scores 34 and 53 were misread as 43 and 35 respectively. The corrected mean equals to:

  6. Out of 6 numbers, the sum of the first 5 numbers is 7 times the 6 th number. If their average is 136, then the 6 th number is:

  7. The average of five numbers is 30. If one number is excluded, then average becomes 31. What is the excluded number?

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  9. The average weight of a class of 50 students is 48.6 kg. If the average weight of the 20 boys is 54 kg, then find the average weight (in kg) of the girls in the class.

  10. In an examination, average marks of a student per paper were 71. If he would have obtained 35 more marks in science; 11 more marks in history and 4 more marks in computer science, his average marks per paper would have been 76. How many papers were there in the examination?


Important Questions from Average

  1. Average of 40 numbers is 71, if the number 100 replaced by 140, then average is increased by

  2. The captain of a football team of 11 members is 28 years old and the goalkeeper is 4 years older than him. If the ages of these two are removed, then the average age of the remaining players is two years less than the average age of the whole team. What is the average age of the team?

  3. There are two Classes A and B having 25 and 30 students respectively. In Class-A the highest score is 21 and lowest score is 17. In Class-B the highest score is 30 and lowest score is 22. Four students are shifted from Class-A to Class-B.

    Consider the following statements:

    1. The average score of Class-B will definitely decrease.

    2. The average score of Class-A will definitely increase.

    Which of the above statements is/are correct?

  4. The average weight of A, B, Cis 40 kg, the average weight of B, D, Eis 42 kg and the weight of Fis equal to that of B. What is the average weight of A, B, C, D, Eand F?

  5. A cow costs more than 4 goats but less than 5 goats. If a goat costs between Rs. 600 and Rs. 800, which of the following is a most valid conclusion?

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