The problem requires us to find the value of an unknown number, denoted as N, given the average of three numbers: 29.75, 18.25, and N. The average is provided as 23.
$ \text{Average} = \frac{\text{Sum of numbers}}{\text{Count of numbers}} $
$ 23 = \frac{29.75 + 18.25 + N}{3} $
$ 29.75 + 18.25 = 48 $
$ 23 = \frac{48 + N}{3} $
$ 23 \times 3 = 48 + N $
$ 69 = 48 + N $
$ N = 69 - 48 $
$ N = 21 $
By following the steps of the average calculation, we determined that the value of the number N is 21.
The average height of 20 students of class 8 is 152 cm and the average height of 15 students of class 9 is 168 cm. What is the average height (to the nearest cm) of the students of both classes?
The average of 4, 6, 8, 12 and x is 7 and the average of x, 9, 13, 15 and y is 9. What is the value of 2x - 3y?
The average weight of 20 girls in a school was 52 kg. Two new students of weight 54 kg and 50 kg were admitted. The ratio of this new average to the old one is:
If the average of two numbers is 13 and the square root of their product is 12, then the difference between the numbers is:
If the average of 5 consecutive odd integers in increasing order is 11 , then the average of the last 3 of them is: