The amount received at 10% per annum compound interest after 3 yrs is Rs. 10,648. What was the principal (in Rs.)?
8000
Using \(A = P\left(1 + \tfrac{R}{100}\right)^n\) with \(R = 10\%\), \(n = 3\):
\[10648 = P \times (1.1)^3 = P \times 1.331\]
\[P = \frac{10648}{1.331} = \mathbf{8000}\]
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