The compound interest on a certain sum of money at 21% p.a. for 2 years is Rs. 11,138.40 (interest compounded yearly). The total amount received (in Rs) after 2 years is:
35,138.40
Compound interest is calculated on the initial principal and also on the accumulated interest from previous periods. It's often described as "interest on interest," and it makes a sum grow faster compared to simple interest.
In this problem, we are given the compound interest earned, the annual interest rate, and the time period. We need to find the total amount received after the given time.
The formula for the Amount (A) after 'n' years with compound interest is:
$$A = P \left(1 + \frac{R}{100}\right)^n$$
Where:
The Compound Interest (CI) is the difference between the Amount and the Principal:
$$CI = A - P$$
Substituting the formula for A into the CI formula:
$$CI = P \left(1 + \frac{R}{100}\right)^n - P$$
$$CI = P \left[ \left(1 + \frac{R}{100}\right)^n - 1 \right]$$
We are given CI, R, and n. We can use the formula to find the Principal (P).
Given: CI = 11138.40, R = 21%, n = 2 years
Substitute the values into the formula:
$$11138.40 = P \left[ \left(1 + \frac{21}{100}\right)^2 - 1 \right]$$
$$11138.40 = P \left[ \left(1 + 0.21\right)^2 - 1 \right]$$
$$11138.40 = P \left[ \left(1.21\right)^2 - 1 \right]$$
Calculate \((1.21)^2\):
$$1.21 \times 1.21 = 1.4641$$
Now substitute this back:
$$11138.40 = P \left[ 1.4641 - 1 \right]$$
$$11138.40 = P \times 0.4641$$
To find P, divide the CI by 0.4641:
$$P = \frac{11138.40}{0.4641}$$
Let's perform the division:
$$P = 24000$$
So, the Principal amount is Rs. 24,000.
The total amount received after 2 years is the sum of the Principal and the Compound Interest.
Total Amount (A) = Principal (P) + Compound Interest (CI)
$$A = 24000 + 11138.40$$
$$A = 35138.40$$
The total amount received after 2 years is Rs. 35,138.40.
| Description | Value (Rs.) |
|---|---|
| Compound Interest (CI) | 11,138.40 |
| Rate (R) | 21% p.a. |
| Time (n) | 2 years |
| Factor for 2 years at 21% CI ($$(1.21)^2 - 1$$) | 0.4641 |
| Calculated Principal (P = CI / Factor) | 24,000.00 |
| Total Amount (A = P + CI) | 35,138.40 |
Starting with a principal of Rs. 24,000, at an annual compound interest rate of 21% for 2 years, the compound interest earned is Rs. 11,138.40. The total amount accumulated at the end of 2 years is Rs. 35,138.40.
| Concept | Description | Formula |
|---|---|---|
| Principal (P) | The initial amount of money invested or borrowed. | - |
| Rate (R) | The percentage at which interest is charged or earned per period. | - |
| Time (n) | The duration for which the money is invested or borrowed. | - |
| Amount (A) | The total sum including the principal and the accumulated interest after a certain period. | $$A = P \left(1 + \frac{R}{100}\right)^n$$ (for yearly compounding) |
| Compound Interest (CI) | The interest calculated on the principal and previously accumulated interest. | $$CI = A - P$$ or $$CI = P \left[ \left(1 + \frac{R}{100}\right)^n - 1 \right]$$ |
The formula for compound interest changes slightly depending on how frequently the interest is compounded within a year (e.g., half-yearly, quarterly, monthly). If interest is compounded 'k' times per year, the formula becomes:
$$A = P \left(1 + \frac{R}{100k}\right)^{nk}$$
And the Compound Interest would be:
$$CI = P \left[ \left(1 + \frac{R}{100k}\right)^{nk} - 1 \right]$$
In this specific problem, the compounding is yearly, which means k=1. So, the simpler formula \(A = P \left(1 + \frac{R}{100}\right)^n\) is applicable.
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