What is the amount (in ₹) of a sum of ₹32,000 at 20% per annum for 9 months, compounded quarterly?
37,044
This problem asks us to calculate the total amount accumulated when a principal sum is invested at a certain rate of interest, compounded quarterly for a specific time period. Understanding the concepts of compound interest and how compounding frequency affects the calculation is crucial here.
Let's identify the key information provided in the question:
When interest is compounded quarterly, the annual interest rate and the total time period need to be adjusted to match the compounding frequency. There are 4 quarters in a year.
The formula for the amount (A) when interest is compounded is:
\[ A = P \left(1 + \frac{r}{100}\right)^n \] where:
Now, let's plug in the values we have:
So, the amount will be:
\[ A = 32000 \left(1 + \frac{5}{100}\right)^3 \]
Let's simplify the expression inside the parentheses:
\[ 1 + \frac{5}{100} = 1 + 0.05 = 1.05 \]
Now substitute this back into the formula:
\[ A = 32000 (1.05)^3 \]
Next, calculate \((1.05)^3\):
\[ (1.05)^3 = 1.05 \times 1.05 \times 1.05 = 1.1025 \times 1.05 = 1.157625 \]
Finally, multiply this by the principal amount:
\[ A = 32000 \times 1.157625 \]
\[ A = 37044 \]
The amount after 9 months, compounded quarterly, is ₹37,044.
| Concept | Description | Formula (Annual Compounding) |
| Principal (P) | The initial amount invested or borrowed. | - |
| Rate (R) | The annual interest rate. | - |
| Time (T) | The duration of the investment/loan in years. | - |
| Compound Amount (A) | Principal + Interest earned over time. | \(A = P\left(1 + \frac{R}{100}\right)^T\) |
| Compound Interest (CI) | The total interest earned over time. | \(CI = A - P\) or \(CI = P\left[\left(1 + \frac{R}{100}\right)^T - 1\right]\) |
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