Signal A passes through a NOT gate and then through an AND gate where the second input is permanently set to logic 1. What is the final output expression?
$Y = Ā$
To solve this problem, we need to understand how NOT and AND gates function in digital electronics.
Understanding the NOT Gate: A NOT gate inverts the input signal. If the input signal is A, the output of the NOT gate would be \overline{A} (the complement of A). This means if A = 1, then \overline{A} = 0, and vice versa.
Understanding the AND Gate: The AND gate outputs a logic 1 only when all inputs are logic 1. In this scenario, the second input of the AND gate is permanently set to logic 1. The inputs to the AND gate are thus \overline{A} and 1.
Therefore, the output of the AND gate is:
This illustrates that the output of the AND gate remains \overline{A}.
Conclusion: Based on the operation of the NOT and AND gates, the final output expression is \overline{A}.
The correct answer is: Y = \overline{A}.
A 2-input NOR gate has one input permanently connected to logic LOW (0). How does the output behave with respect to the other input?
A two-input logic gate is giving high output only when both the inputs are high. For all other input conditions, the output is low. Select the correct logic gate.
The output is high only if one of the input is high. The above statement represents _____
The number of gate inputs, required to realize expression ABC + AB̅CD + EF̅ + AD is
Which of the following is logically equivalent?
A. ¬p → (q → r) and q → (p ∨ r)
B. (p → q) → r and p → (q → r)
C. (p → q) → (r → s) and (p → r) → (q → s)
Choose the correct answer from the options given below :
Consider the expression Y = P ⨁ Q ⨁ R where P, Q, R are the input variables and Y is the output variable. Y will be logic 0 if
(A) an odd number of input variables are 1
(B) an even number of input variables are 1
(C) an odd number of inputs variables are 0
(D) an even number of input variable are 0
(E) an odd number of input variable between 0 and 1
Choose the correct answer from the options given below: