Shyam drives his car 30 km at a speed of 45 km/h and, for the next 1 h 20 m, he drives it at a speed of 51 km/h. Find his average speed (in km/h) for the entire journey.
49
To find the average speed for the entire journey, we need to calculate the total distance covered and the total time taken. The journey is described in two parts, each with a different speed and duration or distance.
The journey consists of two distinct parts:
In the first part of the journey, we are given the distance and the speed. We need to find the time taken for this part.
Using the formula, the time taken for Part 1 is:
\( T_1 = \frac{D_1}{S_1} = \frac{30 \text{ km}}{45 \text{ km/h}} \)
\( T_1 = \frac{30}{45} \text{ hours} = \frac{2}{3} \text{ hours} \)
In the second part of the journey, we are given the time and the speed. We need to find the distance covered in this part.
First, let's convert the time for Part 2 into hours. 20 minutes is equal to \( \frac{20}{60} \) hours = \( \frac{1}{3} \) hours.
So, \( T_2 = 1 \text{ hour} + \frac{1}{3} \text{ hours} = \frac{3}{3} \text{ hours} + \frac{1}{3} \text{ hours} = \frac{4}{3} \text{ hours} \)
Now, using the formula, the distance covered in Part 2 is:
\( D_2 = S_2 \times T_2 = 51 \text{ km/h} \times \frac{4}{3} \text{ hours} \)
\( D_2 = \frac{51 \times 4}{3} \text{ km} = 17 \times 4 \text{ km} = 68 \text{ km} \)
To find the average speed for the entire journey, we sum the distances and the times from both parts.
Total Distance:
\( D_{total} = D_1 + D_2 = 30 \text{ km} + 68 \text{ km} = 98 \text{ km} \)
Total Time:
\( T_{total} = T_1 + T_2 = \frac{2}{3} \text{ hours} + \frac{4}{3} \text{ hours} = \frac{2 + 4}{3} \text{ hours} = \frac{6}{3} \text{ hours} = 2 \text{ hours} \)
The formula for average speed is:
\( \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \)
Using the calculated total distance and total time:
\( \text{Average Speed} = \frac{98 \text{ km}}{2 \text{ hours}} \)
\( \text{Average Speed} = 49 \text{ km/h} \)
The average speed for Shyam's entire journey is 49 km/h.
| Journey Part | Distance | Speed | Time |
|---|---|---|---|
| Part 1 | 30 km | 45 km/h | \( \frac{30}{45} = \frac{2}{3} \) h |
| Part 2 | \( 51 \times \frac{4}{3} = 68 \) km | 51 km/h | 1 h 20 m = \( \frac{4}{3} \) h |
| Total | \( 30 + 68 = 98 \) km | - | \( \frac{2}{3} + \frac{4}{3} = 2 \) h |
Average Speed = \( \frac{\text{Total Distance}}{\text{Total Time}} = \frac{98 \text{ km}}{2 \text{ h}} = 49 \text{ km/h} \)
| Concept | Definition/Formula | Notes |
|---|---|---|
| Speed | Distance covered per unit of time. \( \text{Speed} = \frac{\text{Distance}}{\text{Time}} \) | Units: km/h, m/s, mph, etc. |
| Distance | The total length of the path traveled. \( \text{Distance} = \text{Speed} \times \text{Time} \) | Units: km, meters, miles, etc. |
| Time | The duration of the journey. \( \text{Time} = \frac{\text{Distance}}{\text{Speed}} \) | Units: hours, minutes, seconds, etc. Ensure consistent units. |
| Average Speed | Total distance covered divided by the total time taken for the entire journey. \( \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \) | Not just the average of speeds if time intervals/distances are different. |
When tackling problems involving average speed, especially those with multiple segments like Shyam's journey, always remember the fundamental principle: calculate the total distance and divide by the total time. Do not simply average the given speeds, as this is only correct if the time taken for each segment is the same.
Key steps often involve:
These steps help ensure you correctly calculate the average speed, accounting for variations in speed and duration across different parts of the journey.
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