All Exams Test series for 1 year @ ₹349 only
Question

Shyam drives his car 30 km at a speed of 45 km/h and, for the next 1 h 20 m, he drives it at a speed of 51 km/h. Find his average speed (in km/h) for the entire journey.

This question was previously asked in
SSC CGL 2020 (Tier-2) Statistics Previous Year Paper 3 (28-Jan-2022)
The correct answer is

49

Calculating Average Speed for a Two-Part Journey

To find the average speed for the entire journey, we need to calculate the total distance covered and the total time taken. The journey is described in two parts, each with a different speed and duration or distance.

Understanding the Journey Segments

The journey consists of two distinct parts:

  • Part 1: Shyam drives 30 km at a speed of 45 km/h.
  • Part 2: Shyam drives for 1 hour 20 minutes at a speed of 51 km/h.

Calculations for Part 1

In the first part of the journey, we are given the distance and the speed. We need to find the time taken for this part.

  • Distance ($D_1$) = 30 km
  • Speed ($S_1$) = 45 km/h
  • Time ($T_1$) = Distance / Speed

Using the formula, the time taken for Part 1 is:

\( T_1 = \frac{D_1}{S_1} = \frac{30 \text{ km}}{45 \text{ km/h}} \)

\( T_1 = \frac{30}{45} \text{ hours} = \frac{2}{3} \text{ hours} \)

Calculations for Part 2

In the second part of the journey, we are given the time and the speed. We need to find the distance covered in this part.

  • Time ($T_2$) = 1 hour 20 minutes
  • Speed ($S_2$) = 51 km/h
  • Distance ($D_2$) = Speed × Time

First, let's convert the time for Part 2 into hours. 20 minutes is equal to \( \frac{20}{60} \) hours = \( \frac{1}{3} \) hours.

So, \( T_2 = 1 \text{ hour} + \frac{1}{3} \text{ hours} = \frac{3}{3} \text{ hours} + \frac{1}{3} \text{ hours} = \frac{4}{3} \text{ hours} \)

Now, using the formula, the distance covered in Part 2 is:

\( D_2 = S_2 \times T_2 = 51 \text{ km/h} \times \frac{4}{3} \text{ hours} \)

\( D_2 = \frac{51 \times 4}{3} \text{ km} = 17 \times 4 \text{ km} = 68 \text{ km} \)

Calculating Total Distance and Total Time

To find the average speed for the entire journey, we sum the distances and the times from both parts.

  • Total Distance ($D_{total}$) = Distance from Part 1 + Distance from Part 2
  • Total Time ($T_{total}$) = Time from Part 1 + Time from Part 2

Total Distance:

\( D_{total} = D_1 + D_2 = 30 \text{ km} + 68 \text{ km} = 98 \text{ km} \)

Total Time:

\( T_{total} = T_1 + T_2 = \frac{2}{3} \text{ hours} + \frac{4}{3} \text{ hours} = \frac{2 + 4}{3} \text{ hours} = \frac{6}{3} \text{ hours} = 2 \text{ hours} \)

Calculating Average Speed

The formula for average speed is:

\( \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \)

Using the calculated total distance and total time:

\( \text{Average Speed} = \frac{98 \text{ km}}{2 \text{ hours}} \)

\( \text{Average Speed} = 49 \text{ km/h} \)

The average speed for Shyam's entire journey is 49 km/h.

Journey Part Distance Speed Time
Part 1 30 km 45 km/h \( \frac{30}{45} = \frac{2}{3} \) h
Part 2 \( 51 \times \frac{4}{3} = 68 \) km 51 km/h 1 h 20 m = \( \frac{4}{3} \) h
Total \( 30 + 68 = 98 \) km - \( \frac{2}{3} + \frac{4}{3} = 2 \) h

Average Speed = \( \frac{\text{Total Distance}}{\text{Total Time}} = \frac{98 \text{ km}}{2 \text{ h}} = 49 \text{ km/h} \)

Revision Table: Key Concepts in Average Speed

Concept Definition/Formula Notes
Speed Distance covered per unit of time. \( \text{Speed} = \frac{\text{Distance}}{\text{Time}} \) Units: km/h, m/s, mph, etc.
Distance The total length of the path traveled. \( \text{Distance} = \text{Speed} \times \text{Time} \) Units: km, meters, miles, etc.
Time The duration of the journey. \( \text{Time} = \frac{\text{Distance}}{\text{Speed}} \) Units: hours, minutes, seconds, etc. Ensure consistent units.
Average Speed Total distance covered divided by the total time taken for the entire journey. \( \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \) Not just the average of speeds if time intervals/distances are different.

Additional Information on Average Speed Problems

When tackling problems involving average speed, especially those with multiple segments like Shyam's journey, always remember the fundamental principle: calculate the total distance and divide by the total time. Do not simply average the given speeds, as this is only correct if the time taken for each segment is the same.

Key steps often involve:

  • Identifying the different segments of the journey.
  • Determining (or calculating) the distance and time for each segment.
  • Ensuring all units (distance and time) are consistent (e.g., all in km and hours, or all in meters and seconds). Convert units if necessary (like minutes to hours).
  • Summing up the distances of all segments to get the total distance.
  • Summing up the times of all segments to get the total time.
  • Applying the average speed formula using the total distance and total time.

These steps help ensure you correctly calculate the average speed, accounting for variations in speed and duration across different parts of the journey.

Was this answer helpful?

Similar Questions

  1. To cover a distance of 144 km in 3.2 hours what should be the average speed of the car in meters/second?

  2. Akhil rides first 12 km at a speed of 16 km/h and further 6 km at a speed of 20 km/h. Find his average speed (in km/h).

  3. A train without stoppage travels with an average speed of 70 km/h, and with stoppage, it travels with the average speed of 56 km/h. How many minutes, does the train stop on an average per hour?

  4. After excluding stoppages, the speed of a bus is 60 kmph and after including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?

  5. A car travels from A to B with 40 Km/h and returns from B to A with 60 Km/h. Its average speed during the whole journey is

  6. A bus travels 150 Km in 3 hours and then travel next 2 hours at 60 Km/hr. Then the average speed of the bus will be

  7. The distance between two stations, A and B, is 428 km. a train starts from station ‘A’ at 6:00 a.m and moves towards station ‘B’ at an average speed of 48 km/h. Another train starts from station ‘B’ at 6:20 a.m and moves towards statin ‘A’ at an average speed of 55 km/h. At what time will the trains meet?

  8. X and Y travel a distance of 90 km each such that the speed of Y is greater than that of X. The sum of their speeds is 100 km/h and the total time taken by both is 3 hours 45 minutes. The ratio of the speed of X to that of Y is:

  9. If a boat goes a certain distance at 30 km/h and comes back the same distance at 20 km/hr, what is the average speed (in km/hr) for the total journey ?

  10. To cover a distance of 81 km in 1.5 hours what should be the average speed of the car in meters/second?


Important Questions from Average Speed

  1. A person covers a certain distance at the speed of 60 kmph and returns to the starting point at a speed of 40 kmph . Find the average speed (in km/hour) of the person for the whole journey.

  2. Kapil travels for 4.5 hours at a speed of 50 km / h and 7.5 hours at a speed of 70 km / h. At the end of it, he finds that he covered only 6/7 of the total distance. At what average speed should he travel so that the remaining distance traveled in 5 hours?

  3. A car has to cover 125 kms in 5 hours. What will be the average speed of the car if it has covered 90 kms in the first 3 hours?

  4. A scooter from P to Q travels at 40 km/h and from Q to P at 30 km/h. What is the average speed of the scooter?

  5. A car covers a distance of 100 km at a speed of 60 km/h and another 200 km at a speed of 75 km/h, what is the average speed of the car in km/h for the whole journey? (correct to one decimal place)

Need Expert Advice?
Upcoming Exams
SSC CGL
September 30, 2026
UPSSSC PET
October 23, 2026
Test Series
SSC CGL img
SSC
SSC CGL (Tier I + Tier II) 2026 Mock Test Series - Latest Pattern
2503 Tests 6 Tests Free
6238 Attempts
4.2(880)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App