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Question

Select the letter-cluster from among the given options that can replace the question mark (?) in the following series.

RSU, NXO, JCI, ?, BMY

The correct answer is

FHC

Analyzing the Letter Series Pattern

The question asks us to find the missing letter cluster in the series: RSU, NXO, JCI, ?, BMY. To solve this, we need to identify the pattern governing the progression of letters in each position within the clusters.

Let's assign a numerical value to each letter based on its position in the English alphabet (A=1, B=2, ..., Z=26).

Letter Position
A 1
B 2
C 3
... ...
Z 26

Now, let's write down the position numbers for each letter cluster in the series:

  • RSU: R(18), S(19), U(21)
  • NXO: N(14), X(24), O(15)
  • JCI: J(10), C(3), I(9)
  • ?: Unknown cluster
  • BMY: B(2), M(13), Y(25)

Pattern for the First Letter

Let's look at the first letters of each cluster: R, N, J, ?, B.

Their positions are: 18, 14, 10, ?, 2.

  • From R(18) to N(14): $14 - 18 = -4$
  • From N(14) to J(10): $10 - 14 = -4$

The pattern for the first letter is a decrease of 4 in the alphabetical position.

Applying this pattern to the third cluster JCI (J=10):

  • Next first letter position: $10 - 4 = 6$

The 6th letter in the alphabet is F. Let's check if this pattern holds for the last step:

  • From F(6) to B(2): $2 - 6 = -4$

This confirms the pattern for the first letter is consistently subtracting 4.

So, the first letter of the missing cluster is F.

Pattern for the Second Letter

Let's look at the second letters of each cluster: S, X, C, ?, M.

Their positions are: 19, 24, 3, ?, 13.

Note that the alphabet wraps around after 26.

  • From S(19) to X(24): $24 - 19 = +5$
  • From X(24) to C(3): Counting from 24, we go X, Y, Z, A, B, C. This is 5 steps forward ($24 + 5 = 29$, and $29 \pmod{26} = 3$). So the difference is +5.

The pattern for the second letter is an increase of 5 in the alphabetical position (wrapping around).

Applying this pattern to the third cluster JCI (C=3):

  • Next second letter position: $3 + 5 = 8$

The 8th letter in the alphabet is H. Let's check if this pattern holds for the last step:

  • From H(8) to M(13): $13 - 8 = +5$

This confirms the pattern for the second letter is consistently adding 5 (with wrap-around).

So, the second letter of the missing cluster is H.

Pattern for the Third Letter

Let's look at the third letters of each cluster: U, O, I, ?, Y.

Their positions are: 21, 15, 9, ?, 25.

  • From U(21) to O(15): $15 - 21 = -6$
  • From O(15) to I(9): $9 - 15 = -6$

Based on the pattern observed so far, the pattern for the third letter appears to be a decrease of 6 in the alphabetical position.

Applying this pattern to the third cluster JCI (I=9):

  • Next third letter position: $9 - 6 = 3$

The 3rd letter in the alphabet is C.

So, based on the consistent pattern for the first three steps, the third letter of the missing cluster is C.

Let's check this against the last step: From C(3) to Y(25). Following the -6 pattern from C(3) would give $3 - 6 = -3$, which corresponds to position $26 - 3 = 23$ (W). This does not match Y(25). There is a discrepancy in the third letter pattern for the final step. However, the pattern (-6) is consistent for the first three differences (U to O, O to I, I to ?).

Forming the Missing Cluster

Based on our analysis of the consistent patterns for the first and second letters, and the pattern for the third letter up to the missing term, the missing letter cluster consists of:

  • First letter: F
  • Second letter: H
  • Third letter: C

Combining these, the missing cluster is FHC.

Checking the Options

Let's compare FHC with the given options:

  1. EHD
  2. EIC
  3. FHC
  4. FID

The cluster FHC matches option 3.

Despite the inconsistency in the third letter pattern from C to Y for the final step, the strong and consistent patterns observed for the first two letters across the entire series, and the consistent -6 pattern for the third letter in the initial steps, strongly indicate that FHC is the intended missing cluster.

Conclusion

The missing letter cluster in the series RSU, NXO, JCI, ?, BMY is FHC.

Revision Table: Series Pattern Summary

Position in Cluster Pattern (Change in alphabetical position) Application to JCI (10, 3, 9) Resulting Letter
1st Letter (J=10) -4 $10 - 4 = 6$ F (6th letter)
2nd Letter (C=3) +5 (with wrap-around) $3 + 5 = 8$ H (8th letter)
3rd Letter (I=9) -6 $9 - 6 = 3$ C (3rd letter)

Additional Information: Letter Series Reasoning

Letter series questions are common in logical reasoning tests. They require you to identify a hidden pattern in a sequence of letters or letter groups. These patterns can involve:

  • Arithmetic progression of letter positions (adding or subtracting a constant number).
  • Geometric progression of letter positions.
  • Alternating patterns (different patterns for different letters or positions).
  • Patterns based on vowels/consonants.
  • Patterns based on mirror images or reverse order of letters.
  • Combining multiple patterns (as seen in this question where each letter position has its own pattern).

Solving these questions effectively involves breaking down the series, analyzing each component (like individual letter positions), identifying the mathematical or logical rule, and applying it to find the missing term. It is important to consider wrap-around effects for patterns involving addition or subtraction near the beginning or end of the alphabet.

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Important Questions from Alphabet Series

  1. Select the letter-cluster from among the given options that can replace the question mark (?) in the following series.

    KMTC, EVOM, OQXG, IZSQ, ?

  2. Select the set of letters that when sequentially placed in the blanks of the given letter series will complete the series.

    k_lmml_mk_mmk_lkkl_m
  3. Select the letter will replace the question mark (?) in the following series.

    C, B, B, C, Z, E, W, H, S, ?, N
  4. Which letter will replace the question mark (?) in the following letter series?

    E, J, N, Q, S, ?

  5. Select the combination of letters that when sequentially placed in the blanks of the given series will complete the series.
    C _ B N _ _ V_ _ H C _ B _ H

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