Select the letter-cluster from among the given options that can replace the question mark (?) in the following series. DJRZ, HDZP, LXHF, PRPV, ?
TLXL
To solve this letter-cluster series problem, we need to identify the pattern followed by each letter position in the given clusters. The series is DJRZ, HDZP, LXHF, PRPV, ?. We will analyze the change in each letter's position in the English alphabet from one cluster to the next. We can assign numerical values to each letter, where A=1, B=2, ..., Z=26.
Let's look at each letter position:
Now, let's apply these patterns to the last cluster, PRPV, to find the next cluster in the series:
By applying the patterns identified, the next letter cluster in the series is TLXL.
| Position | Letters in Series | Pattern (Change in Position) | Next Letter Calculation | Next Letter |
|---|---|---|---|---|
| 1st | D, H, L, P | +4 | P (16) + 4 = 20 | T |
| 2nd | J, D, X, R | -6 (cyclic) | R (18) - 6 = 12 | L |
| 3rd | R, Z, H, P | +8 (cyclic) | P (16) + 8 = 24 | X |
| 4th | Z, P, F, V | -10 (cyclic) | V (22) - 10 = 12 | L |
Alphabetical series questions are common in logical reasoning tests. They involve finding a pattern in a sequence of letters or letter clusters. The patterns can be based on:
It is often helpful to write down the alphabetical positions of the letters to easily identify the numerical pattern. Remember to consider cyclic patterns where the alphabet wraps around from Z to A or A to Z.
Select the letter-cluster from among the given options that can replace the question mark (?) in the following series.
KMTC, EVOM, OQXG, IZSQ, ?
Select the set of letters that when sequentially placed in the blanks of the given letter series will complete the series.
k_lmml_mk_mmk_lkkl_mSelect the letter will replace the question mark (?) in the following series.
C, B, B, C, Z, E, W, H, S, ?, NWhich letter will replace the question mark (?) in the following letter series?
E, J, N, Q, S, ?
Select the combination of letters that when sequentially placed in the blanks of the given series will complete the series.
C _ B N _ _ V_ _ H C _ B _ H