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Question

Read the given statements and conclusions carefully. You have to take the given statements to be true even if they seem to be at variance from commonly known facts and decide which conclusion(s) logically follow(s) from the given statements.
Statements:
Some cars are bikes.
All bikes are trucks.
Conclusions:
(I) Some trucks are cars.
(II) All trucks are cars.

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is

Only conclusion (I) follows

Analyzing Statements and Conclusions about Cars, Bikes, and Trucks

This problem requires us to analyze two given statements and determine which of the provided conclusions logically follow from them. We must assume the statements are true, even if they seem unusual.

Analyzing Statement 1: Some cars are bikes

This statement tells us that there is at least one car that is also a bike. The set of 'cars' and the set of 'bikes' have a non-empty intersection. In logical terms, we can represent this as:

\( \text{Cars} \cap \text{Bikes} \neq \emptyset \)

This means there's an overlap between these two categories.

Analyzing Statement 2: All bikes are trucks

This statement indicates that every single bike is also a truck. The entire set of 'bikes' is contained within the set of 'trucks'. We can represent this as:

\( \text{Bikes} \subseteq \text{Trucks} \)

This means the 'Bikes' category is a subset of the 'Trucks' category.

Evaluating Conclusion (I): Some trucks are cars

Let's see if this conclusion follows. We know from Statement 1 that some cars are bikes (\( \text{Cars} \cap \text{Bikes} \neq \emptyset \)). We also know from Statement 2 that all these bikes are trucks (\( \text{Bikes} \subseteq \text{Trucks} \)).

Since the cars that are bikes are definitely trucks (because all bikes are trucks), it logically follows that those specific vehicles are both trucks *and* cars. Therefore, there must be some trucks that are also cars.

Using set notation, if \( \text{Cars} \cap \text{Bikes} \neq \emptyset \) and \( \text{Bikes} \subseteq \text{Trucks} \), then the elements in \( \text{Cars} \cap \text{Bikes} \) must also be in \( \text{Trucks} \). This implies that \( \text{Cars} \cap \text{Trucks} \neq \emptyset \).

Thus, Conclusion (I) logically follows from the statements.

Evaluating Conclusion (II): All trucks are cars

Now let's consider if all trucks are necessarily cars. We know that the set of bikes is within the set of trucks (\( \text{Bikes} \subseteq \text{Trucks} \)), and that some cars overlap with bikes (\( \text{Cars} \cap \text{Bikes} \neq \emptyset \)).

However, the set of trucks (\( \text{Trucks} \)) could potentially be much larger than the set of bikes (\( \text{Bikes} \)). There might be many trucks that are not bikes. Statement 1 only establishes a connection between *some* cars and bikes, not all cars or all trucks. We cannot conclude that the entire set of trucks is contained within the set of cars. For example, there could be trucks that are not bikes and also not cars.

Therefore, Conclusion (II) does not logically follow from the given statements.

Final Deduction

Based on the analysis:

  • Conclusion (I) logically follows.
  • Conclusion (II) does not logically follow.

Therefore, only conclusion (I) is valid.

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Important Questions from Syllogism

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    Some rings are toys.

    Some toys are dolls.

    Conclusions:

    I. Some rings are bangles.

    II. Some dolls are rings.
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