Ram is 20 years younger than Shyam. 5 years ago, the ratio of their age was 3:5. The sum of their present age is
90 years
Let Ram's present age be \( x \) and Shyam's present age be \( x + 20 \).
Five years ago, their ages were \( x - 5 \) and \( x + 20 - 5 = x + 15 \), respectively.
According to the problem, the ratio of their ages five years ago was 3:5:
\[
\frac{x - 5}{x + 15} = \frac{3}{5}
\]
Cross-multiply to solve for \( x \):
\[
5(x - 5) = 3(x + 15)
\]
\[
5x - 25 = 3x + 45
\]
\[
5x - 3x = 45 + 25
\]
\[
2x = 70
\]
\[
x = 35
\]
So, Ram's present age is 35 years and Shyam's present age is \( 35 + 20 = 55 \) years.
The sum of their present ages = \( 35 + 55 = 90 \) years.
Hence, the correct answer is 90 years.
One year ago, the age of B was twice that of A. After 9 years, if the ratio of the ages of B and A would be 4 : 3, then the sum of their present ages is ____ years.
A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years. Then what is the present age of the wife?
The average age of a husband and his wife was 20 years at the time of their marriage. After 6 years, they have a 2 -year old child. Find the present average age of the family.
The ratio of the ages of A, B and C, 5 years ago, was 4 : 5 : 7. The sum of their present ages is 135 years. What will be the sum of the ages (in years) of B and C, 3 years from now?
The ratio of the present age of Mahesh and Ajay is 3 : 2 respectively. After 8 years. Ratio of their age will be 11: 8. What will be the present age of Mahesh’s son if his age is half of the present age of Ajay?
In a school, the average age of boys and girls together is 16.8 years, the average age of boys is 15.4 years, and the average age of girls is 18.2 years. The ratio of number of boys to girls in the school is:
The difference between age of Sunita and Sheela is 12 years. If 9 years ago, elder's age was 4 times of younger's age, then what are their present age?
A. 11 and 23
B. 15 and 27
C. 13 and 25
D. 23 and 35