Ram can do a piece of work in 18 hours. Shyam and Naresh can do it in 9 hours. Ram and Naresh can do it in 12 hours. How long will Shyam alone take to do it?
12 hours
This problem involves calculating the time taken by an individual to complete a task based on the time taken by others, both individually and in combination. The key concept here is the work rate, which is the amount of work done per unit of time.
If a person can complete a piece of work in \(T\) hours, their work rate is \(1/T\) of the work per hour. When multiple people work together, their work rates add up to find their combined work rate.
From the given information, we can find the work rate of each person or combination:
We know the combined work rate of Ram and Naresh, and Ram's individual work rate. We can subtract Ram's rate from the combined rate to find Naresh's rate:
Naresh's work rate = (Ram and Naresh's combined rate) - (Ram's work rate)
Naresh's work rate = \(\frac{1}{12} - \frac{1}{18}\)
To subtract these fractions, we find a common denominator, which is 36.
Naresh's work rate = \(\frac{3}{36} - \frac{2}{36}\)
Naresh's work rate = \(\frac{1}{36}\) work/hour.
This means Naresh alone takes 36 hours to complete the work.
We know the combined work rate of Shyam and Naresh, and we just found Naresh's individual work rate. We can subtract Naresh's rate from the combined rate to find Shyam's rate:
Shyam's work rate = (Shyam and Naresh's combined rate) - (Naresh's work rate)
Shyam's work rate = \(\frac{1}{9} - \frac{1}{36}\)
To subtract these fractions, we find a common denominator, which is 36.
Shyam's work rate = \(\frac{4}{36} - \frac{1}{36}\)
Shyam's work rate = \(\frac{3}{36}\)
Shyam's work rate = \(\frac{1}{12}\) work/hour.
Shyam's work rate is \(\frac{1}{12}\) work/hour. The time taken by Shyam alone is the reciprocal of his work rate.
Time taken by Shyam = \(\frac{1}{\text{Shyam's work rate}}\)
Time taken by Shyam = \(\frac{1}{\frac{1}{12}}\)
Time taken by Shyam = \(1 \times 12\)
Time taken by Shyam = 12 hours.
Therefore, Shyam alone will take 12 hours to do the piece of work.
| Concept | Formula/Relation | Explanation |
|---|---|---|
| Work Rate | Work Rate = \( \frac{1}{\text{Time taken}} \) | The amount of work done per unit of time. |
| Total Work | Total Work = Rate \(\times\) Time | Often considered as 1 unit for a single task. |
| Combined Rate | Rate\(_1\) + Rate\(_2\) + ... | Sum of individual work rates when people work together. |
| Time from Rate | Time = \( \frac{1}{\text{Work Rate}} \) | Inverse relationship between rate and time for a fixed amount of work. |
The concept of work rate is closely related to efficiency. A higher work rate means higher efficiency, as more work is done in the same amount of time. Problems might sometimes refer to people being 'twice as efficient' as others, which directly relates their work rates. If person A is twice as efficient as person B, A's work rate is double B's work rate. Consequently, A would take half the time B takes to do the same work.
Efficiency is inversely proportional to the time taken, assuming the total amount of work is constant.
Mohan can do a piece of work in 10 days and Sohan in 15 days. They started working together, but after 3 days Mohan left the work . What time will Sohan take to finish the work?
A tank is filled in 8 hours by three taps A, B and C. The tap C is thrice as fast as B and B is twice as fast as A. How much time will pipe B alone take to fill the tank?
Had been one menless, then the number of days required to do a piece of work would have been one more. If the number of Man. Days required to complete the work is 56, how many workers were there?
A can do a piece of work in 16 hours, B and C can do it in 8 hours while A and C can do it 12 hours. How long will B alone take to do it?