Radha bought a fridge and a washing machine together for Rs. 57300. She sold the fridge at a profit of 15% and washing machine at a loss of 24% and both are sold at the same price. The cost price of washing machine (in Rs.) is:
34500
This problem involves calculating the original cost price of a washing machine given the total cost of a fridge and washing machine, the profit/loss percentages on their sales, and the fact that they were sold at the same price.
Let the cost price of the fridge be \(C_F\) and the cost price of the washing machine be \(C_W\).
From the problem statement, we have the following relationship for the total cost price:
\(C_F + C_W = 57300 \quad (1)\)
Now, let's look at the selling prices. The selling price (SP) is calculated differently for profit and loss:
Profit/Loss is given as a percentage of the cost price.
The selling price of the fridge (\(S_F\)) is:
\(S_F = C_F + 0.15 C_F = C_F (1 + 0.15) = 1.15 C_F\)
The selling price of the washing machine (\(S_W\)) is:
\(S_W = C_W - 0.24 C_W = C_W (1 - 0.24) = 0.76 C_W\)
The problem states that the selling prices are the same:
\(S_F = S_W\)
So, we have:
\(1.15 C_F = 0.76 C_W \quad (2)\)
We now have a system of two linear equations with two variables (\(C_F\) and \(C_W\)):
From equation (2), we can express \(C_F\) in terms of \(C_W\):
\(C_F = \frac{0.76}{1.15} C_W\)
To simplify the fraction, multiply the numerator and denominator by 100:
\(C_F = \frac{76}{115} C_W\)
Now, substitute this expression for \(C_F\) into equation (1):
\(\frac{76}{115} C_W + C_W = 57300\)
Combine the \(C_W\) terms:
\(\left(\frac{76}{115} + 1\right) C_W = 57300\)
\(\left(\frac{76 + 115}{115}\right) C_W = 57300\)
\(\left(\frac{191}{115}\right) C_W = 57300\)
Now, solve for \(C_W\):
\(C_W = 57300 \times \frac{115}{191}\)
Let's perform the division:
\(57300 \div 191\)
We can see that \(191 \times 3 = 573\). So, \(57300 \div 191 = 300\).
\(C_W = 300 \times 115\)
\(C_W = 34500\)
So, the cost price of the washing machine is Rs. 34500.
We can also find the cost price of the fridge to verify:
\(C_F = 57300 - C_W = 57300 - 34500 = 22800\)
Let's check the selling prices:
\(S_F = 1.15 \times C_F = 1.15 \times 22800 = 26220\)
\(S_W = 0.76 \times C_W = 0.76 \times 34500 = 26220\)
Since \(S_F = S_W = 26220\), our calculation is correct.
The cost price of the washing machine is Rs. 34500.
| Concept | Formula (as a decimal) | Formula (as a fraction) |
|---|---|---|
| Selling Price (with Profit) | \(SP = CP \times (1 + \text{Profit %})\) | \(SP = CP \times \left(1 + \frac{\text{Profit %}}{100}\right)\) |
| Selling Price (with Loss) | \(SP = CP \times (1 - \text{Loss %})\) | \(SP = CP \times \left(1 - \frac{\text{Loss %}}{100}\right)\) |
Understanding the basic concepts of cost price, selling price, profit, and loss is crucial for solving such problems.
In this problem, we used the direct relationship between CP and SP based on the percentage profit or loss. If an item is sold at a 15% profit, the selling price is 115% of the cost price (100% CP + 15% Profit). If an item is sold at a 24% loss, the selling price is 76% of the cost price (100% CP - 24% Loss). These relationships are represented by the factors 1.15 and 0.76 in our calculations.
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