First, we determine the rate at which each pipe fills the tank per hour:
To find the combined rate when all pipes operate together, we add their individual rates:
Combined Rate = Rate A + Rate B + Rate C
Combined Rate = $\frac{1}{12} + \frac{1}{22} + \frac{1}{8}$
To add these fractions, we find the least common multiple (LCM) of the denominators (12, 22, and 8). The LCM is 264.
Combined Rate = $\frac{1 \times 22}{12 \times 22} + \frac{1 \times 12}{22 \times 12} + \frac{1 \times 33}{8 \times 33}$
Combined Rate = $\frac{22}{264} + \frac{12}{264} + \frac{33}{264}$
Combined Rate = $\frac{22 + 12 + 33}{264} = \frac{67}{264}$ of the tank per hour.
The total time taken to fill the tank is the reciprocal of the combined rate:
Time = $\frac{1}{\text{Combined Rate}}$
Time = $\frac{1}{\frac{67}{264}} = \frac{264}{67}$ hours.
To express this as a mixed number:
$264 \div 67 = 3$ with a remainder of $63$.
Therefore, the time taken is $3 \frac{63}{67}$ hours.
Two taps can fill a cistern in 4 hours and 9 hours, respectively. A third tap can empty it in 9 hours. How long (in hours) will it take to fill one-fourth of the empty cistern if all the taps are opened together?
Pipes A, B and C can together fill a tank in 6 hours. After working together for 2 hours, C is closed and A and B together fill the remaining part in 7 hours. The time taken (in hours) by C alone to fill the tank is:
Two pipes A and B can independently fill a tank completely in 20 and 30 minutes respectively. If both the pipes are opened simultaneously, how much time will they take to fill the tank completely?
The compound interest on Rs. 64,000 for 3 years, compounded annually at 7.5% p.a. is
A water tank can be emptied in 40 minutes by a pipe of d 'diameter, so how long will it take for a 2d diameter pipe to be emptied?
A pipe can fill a tank in 4 hours, while a leak which is at one-fourth of the height of the tank from bottom can empty upto that part in 2 hours. If both are operated simultaneously and initially the tank is full, then when it will be one-fourth full?
Two pipes X and Y can fill an empty tank in 16 hours and 20 hours respectively. Pipe Z alone can empty the completely filled tank in 25 hours. Firstly both pipes X and Y are opened and after 6 hours pipe Z is also opened. What will be the total time (in hours) taken to completely fill the tank?