The rate at which the inlet pipe fills the tank is the reciprocal of the time it takes to fill it.
When both pipes are open, the net rate is the difference between the filling rate and the emptying rate.
Net filling rate = Inlet rate - Outlet rate
Net filling rate = $\frac{1}{4} - \frac{1}{6}$
To subtract, find a common denominator, which is 12:
Net filling rate = $\frac{3}{12} - \frac{2}{12} = \frac{1}{12}$ of the tank per hour.
The net rate of $\frac{1}{12}$ means the tank fills completely in 12 hours (since Time = Total Work / Rate = $1 \div \frac{1}{12} = 12$ hours).
We need to find the time to fill half the tank (i.e., $\frac{1}{2}$ of the tank).
Time to half-fill = (Amount to fill) / (Net filling rate)
Time to half-fill = $\frac{1}{2} \div \frac{1}{12}$
Time to half-fill = $\frac{1}{2} \times 12 = 6$ hours.
Therefore, the tank will be half-full in 6 hours.
A pipe can fill a cistern in 20 minutes where as the cistern when full can be emptied by a leak in 28 minutes. When both are opened, The time taken to fill the cistern is:
‘A’ pipe can empty a tank in 20 minutes. The second pipe ‘B’ has a diameter twice as that of ‘A’. If both A & B pipe are attached to the tank how much time will be required to empty the tank?
Pipes A and B can empty a full tank in 16 hours and 24 hours, respectively. Pipe C alone can fill the empty tank in 4 hours. If A, B and C are opened together, the tank will be 35% full after :
Pipes A and B can fill a tank in 36 minutes and 45 minutes, respectively. Both these pipes were opened simultaneously. After 20 minutes, a leak at the bottom of the tank was spotted which was immediately sealed. The tank was full in another 15 minutes. The leak alone can empty the full tank in:
A cistern has a leak which would empty it in 6 hours. A tap is turned on which admits 10 litres of water per minute into the cistern. When it is full it is now emptied in 10 hours. What is the capacity (in litres) of the cistern?