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Question

P and Q take part in 400 m race. P runs at 12 km/hr. P gives Q a start of 20 m and still beats him by 13 seconds. The speed of Q is: (Round up to two decimal places.)

This question was previously asked in
SSC CGL 2024 (Tier-I) Previous Year Paper (17-Sep-2024) (Shift 3)
The correct answer is

10.29 km/hr

Let the speed of Q be v km/hr. 

Speed of P = 12 km/hr 

Distance covered by P = 400 m = 0.4 km 

Distance covered by Q = 400 - 20 = 380 m = 0.38 km 

Time taken by P = 0.4/12 hr = 1/30 hr = 2 min 

Time taken by Q = 0.38/v hr 

Given that P beats Q by 13 seconds = 13/3600 hr 

Time taken by Q = Time taken by P + 13/3600 0.38/v = 1/30 + 13/3600 0.38/v 

= (120 + 13)/3600 = 133/3600 v = 0.38 * 3600 / 133 v = 10.29 km/hr (approximately)

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