Two questions sort all four spectra: does it have ripples, and is it centred at the origin or split in two?

Ripples mean a rectangular time window. A sharp-edged pulse transforms to a sinc, whose side lobes are the ripples:

\(\text{rect}(t/\tau)\ \longleftrightarrow\ \tau\,\text{sinc}\!\left(\dfrac{\omega\tau}{2}\right)\)

A smooth, gradually decaying time function transforms to a smooth, ripple-free spectrum. So (i) and (iv) belong to the rectangular family, and (ii) and (iii) to the exponential family.

Two lobes mean multiplication by a sinusoid. Multiplying any signal by \(\cos\omega_0t\) shifts its spectrum to \(\pm\omega_0\):

\(x(t)\cos\omega_0t\ \longleftrightarrow\ \tfrac{1}{2}\left[X(\omega-\omega_0)+X(\omega+\omega_0)\right]\)

So a single central lobe means no carrier; a split pair means the signal oscillates.

Now assign all four.

which is option 4.

The two ripple-free spectra confirmed. The double-sided exponential gives a Lorentzian centred at zero,

\(e^{-a|t|}\ \longleftrightarrow\ \dfrac{2a}{a^{2}+\omega^{2}}\)

and the damped sine is that same Lorentzian shape shifted to \(\pm\omega_0\):

\(e^{-at}\sin\omega_0t\,u(t)\ \longleftrightarrow\ \dfrac{\omega_0}{(a+j\omega)^{2}+\omega_0^{2}}\)

The underlying principle. Smoothness in one domain buys compactness in the other. A discontinuity in time — the vertical edge of a rectangle — forces the spectrum to decay only as 1/ω, which is what the ripples are; a signal with no discontinuity decays far faster. This is exactly why window functions such as Hamming and Hanning are used in spectral analysis: rounding the edges of the observation window suppresses the side lobes.

Hence, the correct matching is a-(iv), b-(ii), c-(i), d-(iii).