Match the chemical conversion in List-I to the appropriate reagent in List-II: Choose the correct answer from the options given below:List-I List-II (A) 
(I) Na2Cr2O7 in presence of H2SO4 (B) CH3CH2OH → C2H5OC2H5 (II) H2SO4 at 443 K (C) 
(III) Zn (D) CH3CH2OH → CH2 = CH2 (IV) H2SO4 at 413 K
(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Explanation of the solution:
- **(A)** Phenol can be converted to **benzene** using **Zn** (zinc) through reduction. This corresponds to **(III)**.
- **(B)** **Ethanol** reacts with **H2SO4 at 443 K** to undergo **dehydration** and form **ethyl ether** (C2H5OC2H5). This corresponds to **(IV)**.
- **(C)** **Phenol** can undergo **oxidation** using **Na2Cr2O7** in the presence of **H2SO4**, leading to the formation of a **quinone** or other products. This corresponds to **(I)**.
- **(D)** **Ethanol** undergoes **dehydration** with **H2SO4 at 413 K** to form **ethylene** (CH2 = CH2). This corresponds to **(II)**.
Thus, the correct answer is **Option (a)**: (A)-(III), (B)-(IV), (C)-(I), (D)-(II).
Phenol is brominated in solvent CS₂ at low temperature. The product formed are:
What is not true regarding compound [B]?
(A) They are higher boiling liquids than aldehydes and ketones due to extensive H bonding
(B) They are soluble in Benzene
(C) They produce alkane when heated with soda lime
(D) Produces CO₂ when treated with NaHCO₃
Choose the correct answer from the options given below:
Which of the following is the correct statement for hybridization of C-atom and number of π bonds in the Carbonyl group?
What is the product formed in the following reaction sequence?

What will be the product formed when cyclohexanone undergoes Aldol condensation?