In simple random sampling of n units from a population of N units the quantity [1 - (n / N)] is called the
finite population correction factor
The question asks to identify the term for the quantity \(\left[1 - \left(\frac{n}{N}\right)\right]\) in the context of simple random sampling of \(n\) units from a population of \(N\) units. This quantity plays a crucial role in survey sampling, particularly when dealing with finite populations. Let's examine the given options.
Comparing the quantity given in the question, \(\left[1 - \left(\frac{n}{N}\right)\right]\), with the definitions above, it exactly matches the definition of the finite population correction factor. This factor is essential for accurately estimating the precision of survey results when the sample size is a significant proportion of the population size.
For instance, the variance of the sample mean (\(\bar{y}\)) in simple random sampling without replacement is given by the formula:
\(Var(\bar{y}) = \frac{S^2}{n} \times \left(\frac{N-n}{N}\right) = \frac{S^2}{n} \times \left[1 - \left(\frac{n}{N}\right)\right]\)
where \(S^2\) is the population variance. Here, the term \(\left[1 - \left(\frac{n}{N}\right)\right]\) is the finite population correction factor. If the population is infinite (\(N \to \infty\)) or sampling is done with replacement, the sampling fraction \(\frac{n}{N}\) approaches 0, and the FPC approaches 1. In such cases, the variance formula simplifies to \(\frac{S^2}{n}\).
| Term | Formula | Description |
|---|---|---|
| Sampling Fraction | \(\frac{n}{N}\) | Proportion of population sampled. |
| Expansion Factor | \(\frac{N}{n}\) | Reciprocal of sampling fraction, used for extrapolation. |
| Finite Population Correction Factor (FPC) | \(\left[1 - \left(\frac{n}{N}\right)\right]\) or \(\left(\frac{N-n}{N}\right)\) | Factor to adjust variance when sampling without replacement from a finite population. |
| Degrees of Freedom | e.g., \(n-1\) | Number of values free to vary in a calculation. |
Based on the definitions, the quantity \(\left[1 - \left(\frac{n}{N}\right)\right]\) is correctly identified as the finite population correction factor.
| Concept | Formula | Importance in Simple Random Sampling |
|---|---|---|
| Sample Size (\(n\)) | \(n\) | Number of units selected from the population. |
| Population Size (\(N\)) | \(N\) | Total number of units in the population. |
| Sampling Fraction | \(\frac{n}{N}\) | Indicates intensity of sampling. |
| Expansion Factor | \(\frac{N}{n}\) | Used for estimating population totals/aggregates from sample data. |
| Finite Population Correction Factor (FPC) | \(\left[1 - \left(\frac{n}{N}\right)\right]\) | Adjusts variance calculations for sampling without replacement from finite populations. Becomes significant when \(n/N\) is large. |
When you sample without replacement from a finite population, as you select units for your sample, the composition of the remaining population changes. This means subsequent selections are not independent in the same way they would be with replacement sampling or sampling from an infinite population. Specifically, if you draw a sample of size \(n=N\) (a census), your sample mean will be exactly equal to the population mean, and the variance of the sample mean will be zero. The finite population correction factor reflects this reduction in variance. When \(n\) is much smaller than \(N\) (e.g., \(n/N < 0.05\)), the FPC is close to 1, and the distinction between sampling with and without replacement becomes negligible in terms of variance. However, when \(n\) is a substantial portion of \(N\), the FPC significantly reduces the estimated variance, providing a more accurate measure of precision for estimates obtained via simple random sampling without replacement.
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