All Exams Test series for 1 year @ ₹349 only
Question

In how many years will a sum of ₹16,000 at 10% per annum compounded semi-annually become ₹18,522?

This question was previously asked in
RRB ALP 2025 CBT 2 Mechanic Motor Vehicle Question Paper (28-Jul-2026) (Shift 1)
The correct answer is

1.5 years

To determine in how many years a sum of ₹16,000 will become ₹18,522 at 10% per annum compounded semi-annually, we use the compound interest formula:

\(A = P \left(1 + \frac{r}{n}\right)^{nt}\)

where:

  • \(A\) is the amount after time \(t\).
  • \(P\) is the principal amount (₹16,000).
  • \(r\) is the annual interest rate (10% or 0.10).
  • \(n\) is the number of times the interest is compounded per year (2 times for semi-annual).
  • \(t\) is the time in years.

Given \(A = 18522, P = 16000, r = 0.10,\) and \(n = 2\), we need to find \(t\).

Plug in the values into the formula:

\(18522 = 16000 \left(1 + \frac{0.10}{2}\right)^{2t}\)

Calculate \(\left(1 + \frac{0.10}{2}\right)\):

\(\left(1 + \frac{0.10}{2}\right) = 1.05\)

Rewrite the equation:

\(18522 = 16000 \times (1.05)^{2t}\)

Divide both sides by 16000:

\(\frac{18522}{16000} = (1.05)^{2t}\)

Simplify the fraction:

\(1.157625 = (1.05)^{2t}\)

To solve for \(t\), take the logarithm of both sides:

\(\log(1.157625) = 2t \cdot \log(1.05)\)

Calculate the logarithms (using a calculator):

  • \(\log(1.157625) \approx 0.063198\)
  • \(\log(1.05) \approx 0.021189\)

Substitute these values into the equation:

\(0.063198 = 2t \cdot 0.021189\)

Solve for \(t\):

\(2t = \frac{0.063198}{0.021189}\)

\(2t \approx 2.982\)

\(t \approx \frac{2.982}{2} = 1.491\)

Round to the nearest half year, we find \(t = 1.5\) years.

Thus, the correct answer is 1.5 years.

Was this answer helpful?

Similar Questions

  1. Find the compound interest on ₹5,70,000 for 1.5 years at 10% per annum compounded half-yearly.

  2. Shams invested Rs. 4000 at 10% per annum compound interest. After n years, Shams received Rs. 1324 more, Find the value of n.

  3. If Rs. 2,000 is invested at the rate of 20% per annum, compounded half yearly, then find the amount after 18 months.

  4. If sum of Rs. 1000 amount to Rs. 1331 in 3 years, compounded annually. Then, find rate of interest per annum?

  5. Find the compound interest on Rs. 62500 at 21% per annum for \(1\frac{1}{2}\)  years compounded half yearly.

  6. Consider the given question and decide which of the following statements is sufficient to answer the question.

    X took a loan from Y on compound interest. Find the rate per annum?

    Statements:

    1. After 3 years, X paid Rs. 500 as interest.

    2. After 3 years, X paid Rs. 1,500 to clear his loan with Y.


Important Questions from Compound Interest

  1. At what rate percent per annum will Rs. 7200 amount to Rs. 7938 in one year, if interest is compounded half yearly?

  2. What is the compound interest (in Rs.) on a sum of Rs. 8192 for \(1 \frac{1}{4}\)  years at 15% per annum, if interest is compounded 5-monthly ?

  3. What is the difference (in Rs.) between the interests on Rs. 50,000 for one year at 8% per annum compounded half yearly and yearly?

  4. A sum of money becomes Rs. 11,880 after 4 years and Rs. 17,820 after 6 years on compound interest, if the interest is compounded annually. What is the half of the sum (in Rs.)?

  5. A sum invested at compound interest amounts to Rs. 7,800 in 3 years and Rs. 11,232 in 5 years. What is the rate per cent?

Need Expert Advice?
Upcoming Exams
RRB NTPC
September 27, 2026
Test Series
RRB ALP img
Railways
RRB ALP 2026 Mock Test series
1035 Tests 1 Tests Free
768 Attempts
4.3(233)
English, Hindi
More Questions from RRB ALP

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App