A sum of money invested at a compound interest amounts to 800 in 2 year and 840 in 3 year. The rate of interest is:
5%
The problem asks us to find the annual rate of interest given the amounts accumulated after two different years under compound interest. We are given the amount after 2 years and the amount after 3 years.
Let P be the principal amount, and r be the annual rate of interest compounded annually.
The amount after n years at compound interest is given by the formula:
\(A = P \left(1 + \frac{r}{100}\right)^n\)
According to the problem:
Using the compound interest formula, we can write:
\(A_2 = P \left(1 + \frac{r}{100}\right)^2 = 800 \quad \ldots (1)\)
\(A_3 = P \left(1 + \frac{r}{100}\right)^3 = 840 \quad \ldots (2)\)
To find the rate of interest (r), we can divide equation (2) by equation (1):
\(\frac{A_3}{A_2} = \frac{P \left(1 + \frac{r}{100}\right)^3}{P \left(1 + \frac{r}{100}\right)^2}\)
\(\frac{840}{800} = \left(1 + \frac{r}{100}\right)^{3-2}\)
\(\frac{840}{800} = 1 + \frac{r}{100}\)
Now, we can solve for \(1 + \frac{r}{100}\):
\(\frac{84}{80} = 1 + \frac{r}{100}\)
\(\frac{21}{20} = 1 + \frac{r}{100}\)
Next, isolate \(\frac{r}{100}\):
\(\frac{r}{100} = \frac{21}{20} - 1\)
\(\frac{r}{100} = \frac{21 - 20}{20}\)
\(\frac{r}{100} = \frac{1}{20}\)
Finally, solve for r:
\(r = \frac{1}{20} \times 100\)
\(r = 5\)
So, the rate of interest is 5% per annum.
Alternatively, we can think of the amount at the end of the 2nd year (800) as the principal for the 3rd year. The interest earned during the 3rd year is the difference between the amount after 3 years and the amount after 2 years.
Interest earned in the 3rd year = \(A_3 - A_2 = 840 - 800 = 40\)
This interest of 40 is earned on the amount at the end of year 2, which is 800, over one year.
Using the simple interest formula for one year (which is equivalent to compound interest for a single year):
Interest = Principal × Rate × Time / 100
\(40 = 800 \times r \times \frac{1}{100}\)
\(40 = 8 \times r\)
\(r = \frac{40}{8}\)
\(r = 5\)
The rate of interest is 5%.
Let's check the options provided:
Our calculated rate of 5% matches the first option.
| Concept | Explanation | Application to Problem |
|---|---|---|
| Compound Interest | Interest calculated on the initial principal and also on the accumulated interest of previous periods. | Amount grows year by year based on the previous year's amount. |
| Amount Formula | \(A = P \left(1 + \frac{r}{100}\right)^n\) | \(A_2 = P \left(1 + \frac{r}{100}\right)^2 = 800\) \(A_3 = P \left(1 + \frac{r}{100}\right)^3 = 840\) |
| Interest in a Specific Year | Amount at the end of year n - Amount at the end of year (n-1). This is the interest earned in year n, calculated on the amount at the end of year (n-1). | Interest in 3rd year = \(A_3 - A_2 = 840 - 800 = 40\). This interest is on 800. |
| Rate Calculation (from one year's growth) | Rate = (\(\frac{\text{Interest}}{\text{Principal for that year}}\)) \(\times 100\) | Rate = (\(\frac{40}{800}\)) \(\times 100 = 5\%\) |
Compound interest is a powerful concept in finance because it allows your money to grow at an accelerating rate. Here are some key points:
Understanding how the amount grows from one year to the next is crucial for solving problems like this one, where the interest for a specific period is calculated on the amount at the beginning of that period.
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