In an examination, a student was asked to divide a certain number by 8. By mistake he multiplied it by 8 and got the answer 2016 more than the correct answer. What was the number?
256
This problem involves setting up an algebraic equation based on the information given about a student's calculation mistake. We need to find the original number that the student was supposed to divide by 8.
Let the unknown number be represented by the variable \(x\).
According to the problem statement, the incorrect answer was 2016 more than the correct answer. This can be written as an equation:
Incorrect Answer = Correct Answer + 2016
\(8x = \frac{x}{8} + 2016\)
Now, we need to solve the equation \(8x = \frac{x}{8} + 2016\) for \(x\).
So, the original number is 256.
Let's check if our answer, \(x=256\), satisfies the condition given in the problem.
The difference is indeed 2016, which matches the problem statement. Thus, our calculated number 256 is correct.
The number the student was asked to divide by 8 was 256.
| Original Number | \(x\) |
|---|---|
| Correct Calculation | \(x \div 8\) |
| Incorrect Calculation | \(x \times 8\) |
| Equation | \(8x = \frac{x}{8} + 2016\) |
| Solution for \(x\) | 256 |
| Step | Description |
|---|---|
| Read Carefully | Understand the problem, identify knowns and unknowns. |
| Assign Variables | Use variables (like \(x\)) for unknown quantities. |
| Formulate Equation | Translate the problem statement into a mathematical equation. |
| Solve Equation | Use algebraic techniques to find the value of the variable. |
| Verify Answer | Check if the solution makes sense in the context of the original problem. |
An algebraic equation is a statement that two mathematical expressions are equal. In this problem, we used a linear equation with one variable. Solving such equations involves isolating the variable on one side of the equation using inverse operations (addition/subtraction, multiplication/division) while maintaining equality.
For example, to solve \(63x = 16128\), we perform the inverse operation of multiplication, which is division. Dividing both sides by 63 gives \(x = \frac{16128}{63}\).
Setting up the correct equation is often the most crucial step in solving word problems like this one involving calculation errors or comparisons between different results.
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