In an exam, 70% candidates passed in physics and 80% candidates passed in reasoning. If 55% candidates passed in both these subjects, what percent of candidates failed in both subjects ?
5%
This problem involves calculating the percentage of candidates who failed in both subjects given the pass percentages for individual subjects and the percentage who passed both. We need to find the group of candidates who are outside the 'passed' categories for both Physics and Reasoning.
To find the percentage of candidates who failed in both, we first need to determine the percentage of candidates who passed in at least one subject (either Physics, Reasoning, or both). We can use the principle of inclusion-exclusion for this.
Let P be the event that a candidate passed in Physics.
Let R be the event that a candidate passed in Reasoning.
We are given:
The percentage of candidates who passed in at least one subject is given by the formula:
$P(P \cup R) = P(P) + P(R) - P(P \cap R)$
Substituting the given values:
$P(P \cup R) = 70\% + 80\% - 55\%$
$P(P \cup R) = 150\% - 55\%$
$P(P \cup R) = 95\%$
So, 95% of the candidates passed in at least one of the subjects.
The total percentage of candidates is always 100%. If 95% of candidates passed in at least one subject, the remaining candidates must have failed in both subjects.
Percentage failed in both = Total Percentage - Percentage passed in at least one subject
Percentage failed in both = $100\% - P(P \cup R)$
Percentage failed in both = $100\% - 95\%$
Percentage failed in both = $5\%$
Therefore, 5% of the candidates failed in both Physics and Reasoning.
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