The sum of the interior angles in any triangle is always $180^\circ$. This fundamental property can be represented by the formula:
$ \text{Angle A} + \text{Angle B} + \text{Angle C} = 180^\circ $
We are given the measures of two angles:
Substitute these values into the formula:
$ 30^\circ + 45^\circ + \text{Angle C} = 180^\circ $
First, sum the known angles:
$ 75^\circ + \text{Angle C} = 180^\circ $
Next, isolate Angle C by subtracting $75^\circ$ from both sides:
$ \text{Angle C} = 180^\circ - 75^\circ $
$ \text{Angle C} = 105^\circ $
Therefore, the measure of angle C is $105^\circ$.
What is the circumcenter of the triangle ABC?
What is the centroid of the triangle ABC?
What is the foot of the altitude from the vertex A of the triangle ABC?
In ΔABC, D is a point on BC such that ∠ADB = 2∠DAC, ∠BAC = 70° and ∠B = 56°. What is the measure of ∠ADC?
In ΔABC, ∠A = 66° and ∠B = 50 °. If the bisectors of ∠B and ∠C meet at P, then ∠BPC – ∠PCA = ?