We are given a triangle \(\Delta\text{ABC}\) with the following side lengths:
To determine if the triangle is right-angled, acute, or obtuse, we use the converse of the Pythagorean theorem. We need to compare the square of the longest side with the sum of the squares of the other two sides.
First, calculate the squares of each side length:
Next, sum the squares of the two shorter sides:
\(\text{AB}^2 + \text{BC}^2 = 256\text{cm}^2 + 3969\text{cm}^2 = 4225\text{cm}^2\)
Compare this sum to the square of the longest side:
We found that \(\text{AB}^2 + \text{BC}^2 = 4225\text{cm}^2\), and \(\text{AC}^2 = 4225\text{cm}^2\). Therefore, \(\text{AB}^2 + \text{BC}^2 = \text{AC}^2\).
According to the converse of the Pythagorean theorem, if \(a^2 + b^2 = c^2\), the triangle is a right-angled triangle. Since the condition is met, triangle \(\Delta\text{ABC}\) is a Right angled Triangle.
In the given figure, if \(RS = 3\sqrt{3} \text{ cm}\) and \(RPS\) is an equilateral triangle, then find the value of \(QR\)
For a pair of similar triangles shown in the figure, the angles made at $B$ and $R$ are same in both the triangles $BAC$ and $RAQ$. If the ratio of the areas of the two triangles is 2:1, and if the area of $BAC$ is $100\text{ cm}^2$ then what is the area of $RAQ$ in sq.cm.?

In a right angled triangle, with angle at A being , the side $AB$ is of length 4cm and $BC$ is 15 cm. What is the length of side $AC$?

What is the angle at $B$ in the triangle $ABC$, if the angle made at $K$ is $30^\circ$ and the triangles shown in the figure are similar?

What is \(AB + BC\) equal to?
In the given figure, if \(RS = 3\sqrt{3} \text{ cm}\) and \(RPS\) is an equilateral triangle, then find the value of \(QR\)
For a pair of similar triangles shown in the figure, the angles made at $B$ and $R$ are same in both the triangles $BAC$ and $RAQ$. If the ratio of the areas of the two triangles is 2:1, and if the area of $BAC$ is $100\text{ cm}^2$ then what is the area of $RAQ$ in sq.cm.?
