The problem involves finding the length of a side in a right-angled triangle using the Pythagorean theorem.
In a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides (legs). The triangle has a right angle at \(A\), making \(BC\) the hypotenuse.
The theorem is stated as:
\(AB^2 + AC^2 = BC^2\)
\(3^2 + AC^2 = 12^2\)
\(9 + AC^2 = 144\)
\(AC^2 = 144 - 9\)
\(AC^2 = 135\)
\(AC = \sqrt{135}\)
Find the prime factors of 135: \(135 = 5 \times 27 = 5 \times 3^3 = 3 \times 3^2 \times 5 = 9 \times 15\).
\(AC = \sqrt{9 \times 15}\)
\(AC = \sqrt{9} \times \sqrt{15}\)
\(AC = 3\sqrt{15} \text{ cm}\)
The length of side \(AC\) is \(3\sqrt{15}\) cm.
In the given figure, if \(RS = 3\sqrt{3} \text{ cm}\) and \(RPS\) is an equilateral triangle, then find the value of \(QR\)
For a pair of similar triangles shown in the figure, the angles made at $B$ and $R$ are same in both the triangles $BAC$ and $RAQ$. If the ratio of the areas of the two triangles is 2:1, and if the area of $BAC$ is $100\text{ cm}^2$ then what is the area of $RAQ$ in sq.cm.?

In a right angled triangle, with angle at A being , the side $AB$ is of length 4cm and $BC$ is 15 cm. What is the length of side $AC$?

What is the angle at $B$ in the triangle $ABC$, if the angle made at $K$ is $30^\circ$ and the triangles shown in the figure are similar?

What is \(AB + BC\) equal to?
In the given figure, if \(RS = 3\sqrt{3} \text{ cm}\) and \(RPS\) is an equilateral triangle, then find the value of \(QR\)
For a pair of similar triangles shown in the figure, the angles made at $B$ and $R$ are same in both the triangles $BAC$ and $RAQ$. If the ratio of the areas of the two triangles is 2:1, and if the area of $BAC$ is $100\text{ cm}^2$ then what is the area of $RAQ$ in sq.cm.?

In a right angled triangle, with angle at A being , the side $AB$ is of length 4cm and $BC$ is 15 cm. What is the length of side $AC$?
