The problem involves finding the length of a side in a right-angled triangle using the Pythagorean theorem.
In a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides (legs). The triangle has a right angle at \(A\), making \(BC\) the hypotenuse.
The theorem is stated as:
\(AB^2 + AC^2 = BC^2\)
\(3^2 + AC^2 = 12^2\)
\(9 + AC^2 = 144\)
\(AC^2 = 144 - 9\)
\(AC^2 = 135\)
\(AC = \sqrt{135}\)
Find the prime factors of 135: \(135 = 5 \times 27 = 5 \times 3^3 = 3 \times 3^2 \times 5 = 9 \times 15\).
\(AC = \sqrt{9 \times 15}\)
\(AC = \sqrt{9} \times \sqrt{15}\)
\(AC = 3\sqrt{15} \text{ cm}\)
The length of side \(AC\) is \(3\sqrt{15}\) cm.
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